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Question #43090
The Question
Consider an ideal LC circuit consisting of an inductor of inductance and a parallel-plate capacitor of capacitance with plate separation . The physical dimensions of the circuit are much smaller than the wavelength of the emitted electromagnetic waves. Due to the time-varying displacement current between the capacitor plates, the system acts as a Hertzian dipole and radiates electromagnetic energy into space. The power radiated by a dipole of moment is given by Larmor's formula , where is the speed of light in vacuum and is the vacuum permeability. Assuming the radiative damping is very small, what is the time taken for the total electromagnetic energy stored in the LC circuit to decrease to of its initial value?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Maxwell's Correction to Ampere's Law|Energy Stored in Inductor|Integration
Why This Question Is Tricky
Common Mistakes
Students often treat ideal LC circuits as purely conservative systems, assuming energy oscillates indefinitely between the electric and magnetic fields.
This question tests the Maxwell correction: the time-varying electric field (displacement current) between the capacitor plates implies the system acts as a radiating dipole antenna.
The trap lies in failing to recognize that radiation introduces a non-conservative energy flux (Poynting vector), acting as an effective radiation resistance.
Furthermore, students who correctly identify the power loss often misapply the energy averaging, confusing the amplitude decay time constant () with the energy decay time constant (), leading to a missing factor of 2.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electromagnetic Waves - Class 12 |
| Concept | Maxwell's Correction to Ampere's Law |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |