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Question #43068

Difficulty: 8/10 | 🟢 Free

The Question

A block of mass m=0.8 kgm = 0.8 \text{ kg} is attached to a spring of force constant k=80 N/mk = 80 \text{ N/m} and undergoes damped oscillations on a smooth horizontal surface. The damping force is non-linear and given by Fd=−cv∣v∣F_d = -c v |v|, where vv is the velocity of the block and c=0.01 kg/mc = 0.01 \text{ kg/m}. At t=0t = 0, the amplitude of oscillation is A0=0.3 mA_0 = 0.3 \text{ m}. Assuming the damping is weak enough that the motion remains approximately sinusoidal over any single cycle, find the approximate number of complete oscillations NN after which the amplitude reduces to AN=0.15 mA_N = 0.15 \text{ m}.

Options

  • A.

    100100

  • B.

    7575

  • C.

    120120

  • D.

    5050

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Bandwidth in RLC|Effective Spring Constant|Differential Equations

Why This Question Is Tricky

Common Mistakes

Students often incorrectly apply the standard linear damping model (where amplitude decays exponentially as A(t)=A0e−γtA(t) = A_0 e^{-\gamma t}) to non-linear drag forces.

By introducing a v2v^2 dependent drag force, the effective damping coefficient becomes proportional to the velocity amplitude, leading to an algebraic (1/t1/t) decay envelope rather than an exponential one.

This question tests the student's ability to abandon rote formulas for the Q-factor and instead derive the amplitude decay from first principles using the Work-Energy Theorem and cycle-averaged power dissipation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAlternating Current - Class 12
ConceptBandwidth in RLC
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree