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Question #43066
The Question
A uniform conducting rod of mass and length is pivoted at one of its ends and can rotate freely in a horizontal plane. A uniform vertical magnetic field exists in the region. The pivot and the free end of the rod are connected via frictionless sliding contacts to a stationary circuit consisting of an inductor of inductance , a capacitor of capacitance , and a resistor of resistance in series. Initially, the rod is at rest and the capacitor is uncharged. At , an impulsive torque is applied to the rod. Assuming the resistance of the rod and the contacts is negligible, what is the Quality Factor () of the subsequent transient electrical oscillations in the circuit?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Quality Factor|Motional EMF in Rotating Rods|Impulsive Torque and Angular Momentum
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to recognize electro-mechanical coupling and its effect on circuit parameters.
A common trap is treating the motional EMF as an independent voltage source, leading students to incorrectly assume the Quality Factor is simply (Option A).
However, by Lenz's Law, the induced current creates a magnetic torque that opposes the rod's rotation.
This back-action couples the mechanical inertia of the rod to the electrical circuit, effectively acting as an additional capacitor.
Students must integrate the rotational equation of motion to find the relationship between angular velocity and charge, and substitute this into Kirchhoff's Voltage Law to derive the effective stiffness (inverse capacitance) of the coupled oscillator.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Alternating Current - Class 12 |
| Concept | Quality Factor (Q-factor) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |