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Question #43062
The Question
A uniform, purely resistive metallic rod of Young's modulus (in ) and coefficient of linear thermal expansion (in ) is rigidly clamped between two fixed, perfectly insulating walls at an initial temperature . The rod has a temperature-dependent electrical resistance , where is the resistance at (in ) and is the temperature coefficient of resistivity (in ). The rod is connected in parallel with a pure inductor, and this parallel combination is driven by an AC source.
In the steady state, the rod reaches a constant temperature . At this steady state, the total RMS current drawn from the AC source is (in ), and the overall power factor of the parallel circuit is . The rod loses heat to the surroundings (which remain at ) at a rate , where is a positive constant (in ).
Assuming the walls do not yield and the rod does not buckle, which of the following expressions gives the compressive thermal stress (in ) developed in the rod in the steady state?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Wattless Current|First Law Application|Thermal Stress in Constrained Rods
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to synthesize AC circuit analysis with thermal expansion and steady-state heat transfer.
The primary trap lies in the misapplication of Joule heating in AC circuits.
Students often memorize without analyzing branch currents.
A common mistake is using the total RMS current to calculate heat (), ignoring that in a parallel circuit, the current through the resistive rod is only the 'wattful' component .
Another trap is incorrectly writing power as , confusing the general power formula with the form.
Furthermore, the problem requires setting up a self-consistent steady-state equation where the input power itself depends on the temperature via the temperature coefficient of resistivity , testing their ability to handle coupled electro-thermal systems.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Alternating Current - Class 12 |
| Concept | Wattless Current |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |