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Question #43050

Difficulty: 8/10 | 🟢 Free

The Question

In a Fresnel's biprism experiment performed in air, a monochromatic point source of light of wavelength λ\lambda is placed at a distance aa from a biprism. The biprism has a refractive index ng=1.5n_g = 1.5 and a small refracting angle α\alpha. The interference fringes are observed on a screen placed at a distance LL from the source. The observed fringe width is β0=0.30 mm\beta_0 = 0.30 \text{ mm}. The entire apparatus is now completely immersed in a transparent liquid of refractive index nl=43n_l = \frac{4}{3}. Assuming the small angle approximation holds, what is the new fringe width β′\beta' observed on the screen?

Options

  • A.

    0.90 \text{ mm}

  • B.

    0.225 \text{ mm}

  • C.

    1.20 \text{ mm}

  • D.

    0.40 \text{ mm}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Fringe Width Invariance|Young's Double Slit Geometry|Microscope Tube Length

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of wave optics and ray optics by exploiting the apparent shift of virtual sources in a refractive medium.

A common trap is assuming the virtual source separation 'd' is a fixed geometric constant, leading students to only scale the wavelength (λ′=λ/nl\lambda' = \lambda/n_l) and incorrectly obtain 0.225 mm0.225 \text{ mm}.

Conversely, students might recalculate the deviation angle using the relative refractive index but forget to scale the wavelength, yielding 1.20 mm1.20 \text{ mm}.

The correct approach requires modifying both the optical path difference geometry and the wavelength, which elegantly cancels the liquid's refractive index nln_l from the final algebraic expression.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWave Optics - Class 12
ConceptFringe Width Invariance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree