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Question #43049

Difficulty: 8/10 | 🟢 Free

The Question

A light source emitting a continuous spectrum of photon energies from Emin=1.50 eVE_{min} = 1.50 \text{ eV} to Emax=4.00 eVE_{max} = 4.00 \text{ eV} illuminates a Young's Double Slit setup with a slit separation of d=1.00 mmd = 1.00 \text{ mm}. A screen is placed at a distance D=2.00 mD = 2.00 \text{ m} from the slits. The screen is coated with a photoelectric material having a work function Φ=2.48 eV\Phi = 2.48 \text{ eV}, and the interference pattern is recorded by mapping the local photoelectric current density on the screen. Determine the minimum distance y>0y > 0 from the central maximum where a bright fringe of the shortest detected wavelength exactly coincides with a dark fringe of the longest detected wavelength. (Take hc=1240 eV⋅nmhc = 1240 \text{ eV}\cdot\text{nm})

Options

  • A.

    2.48 \text{ mm}

  • B.

    4.96 \text{ mm}

  • C.

    15.5 \text{ mm}

  • D.

    31.0 \text{ mm}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Fringe Width Invariance|Einstein's Photoelectric Equation|Maxwell-Boltzmann Distribution

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of Wave Optics and the Photoelectric Effect.

The primary trap lies in identifying the effective spectrum that contributes to the observed interference pattern.

Students often mechanically use the source's minimum and maximum emission energies (1.50 eV1.50 \text{ eV} to 4.00 eV4.00 \text{ eV}) to find the wavelength boundaries, ignoring the physical detection mechanism.

By doing so, they calculate the longest wavelength as 826.67 nm826.67 \text{ nm} instead of the photoelectric threshold wavelength of 500 nm500 \text{ nm}, leading to the incorrect coincidence distance of 2.48 mm2.48 \text{ mm}.

The problem requires recognizing that the work function acts as a high-pass energy filter (or low-pass wavelength filter) for the interference fringes.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWave Optics - Class 12
ConceptFringe Width Invariance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree