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Question #43048

Difficulty: 8/10 | 🟢 Free

The Question

A hydrogen-like heavy ion of atomic number ZZ has an electron (rest mass m0m_0, charge −e-e) in a circular orbit corresponding to the principal quantum number nn. The Bohr quantization condition applies to the relativistic angular momentum, i.e., L=γm0vr=nℏL = \gamma m_0 v r = n\hbar, where γ=(1−v2/c2)−1/2\gamma = (1-v^2/c^2)^{-1/2} and cc is the speed of light. If the binding energy of the electron in this orbit is BB (defined such that the total relativistic energy including rest mass is E=m0c2−BE = m_0 c^2 - B), which of the following expressions correctly represents the orbital magnetic dipole moment μ\mu of the electron? (Here μB=eℏ2m0\mu_B = \frac{e\hbar}{2m_0} is the classical Bohr magneton).

Options

  • A.

    nμB(1−Bm0c2)n \mu_B \left( 1 - \frac{B}{m_0 c^2} \right)

  • B.

    nμB(1+Bm0c2)n \mu_B \left( 1 + \frac{B}{m_0 c^2} \right)

  • C.

    nμB(1−Bm0c2)−1n \mu_B \left( 1 - \frac{B}{m_0 c^2} \right)^{-1}

  • D.

    nμBn \mu_B

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Magnetic Moment of Orbiting Electron|Mass Defect vs. Binding Energy|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the limits of the classical gyromagnetic ratio when an electron is in a deep potential well (high ZZ), requiring a semi-relativistic treatment.

Students commonly fall into the trap of blindly applying the classical formula μ=nμB\mu = n \mu_B (Option D), ignoring that the effective relativistic mass m=γm0m = \gamma m_0 attenuates the magnetic moment.

Furthermore, it tests the correct application of mass-energy equivalence: students often misinterpret relativistic mass increase, failing to realize that the localized binding energy BB actually reduces the total energy of the bound system (E=m0c2−BE = m_0 c^2 - B), which elegantly links the Lorentz factor γ\gamma directly to the binding energy via E=m0c2/γE = m_0 c^2 / \gamma.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptMagnetic Moment of Orbiting Electron
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree