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Question #43039

Difficulty: 8/10 | 🟢 Free

The Question

A modified moving coil galvanometer has a coil resistance Rg=18 ΩR_g = 18 \ \Omega. Instead of a standard torsional spring, its restoring torque is provided by a small pendulum mass attached to the coil's pivot, making the restoring torque directly proportional to the effective acceleration due to gravity. When stationary in an inertial frame on Earth, it is converted into an ammeter of maximum range I0I_0 using a shunt resistance S1=2 ΩS_1 = 2 \ \Omega. The ammeter is subsequently mounted inside an elevator accelerating vertically upwards at a=ga = g (where gg is the acceleration due to gravity). To ensure the ammeter still measures the exact same maximum full-scale current I0I_0 in this accelerating frame, a new shunt resistance S2S_2 is required. Calculate the value of S2S_2.

Options

  • A.

    4.5 Ω4.5 \ \Omega

  • B.

    2.0 Ω2.0 \ \Omega

  • C.

    4.0 Ω4.0 \ \Omega

  • D.

    3.6 Ω3.6 \ \Omega

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Shunt Resistance Conversion|Apparent Weight in Accelerating Elevators|Rigid Body Constraints

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of non-inertial frame dynamics with electrodynamic instrumentation.

The primary trap is the assumption that a galvanometer's full-scale deflection current (IgI_g) is an invariant electrical property.

Students often misapply the shunt formula by keeping IgI_g constant, ignoring that the mechanical restoring torque—and thus the required magnetic deflecting torque—depends on the effective gravity (geffg_{\text{eff}}) in the accelerating frame.

By using a gravity-based restoring mechanism, the problem forces the realization that Ig∝geffI_g \propto g_{\text{eff}}.

Secondary traps involve incorrectly scaling the shunt resistance linearly with geffg_{\text{eff}} (yielding 4.0 Ω4.0 \ \Omega) or approximating the shunt formula by ignoring the galvanometer current in the denominator (yielding 3.6 Ω3.6 \ \Omega).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptShunt Resistance Conversion
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree