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Question #43039
The Question
A modified moving coil galvanometer has a coil resistance . Instead of a standard torsional spring, its restoring torque is provided by a small pendulum mass attached to the coil's pivot, making the restoring torque directly proportional to the effective acceleration due to gravity. When stationary in an inertial frame on Earth, it is converted into an ammeter of maximum range using a shunt resistance . The ammeter is subsequently mounted inside an elevator accelerating vertically upwards at (where is the acceleration due to gravity). To ensure the ammeter still measures the exact same maximum full-scale current in this accelerating frame, a new shunt resistance is required. Calculate the value of .
Options
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- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Shunt Resistance Conversion|Apparent Weight in Accelerating Elevators|Rigid Body Constraints
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of non-inertial frame dynamics with electrodynamic instrumentation.
The primary trap is the assumption that a galvanometer's full-scale deflection current () is an invariant electrical property.
Students often misapply the shunt formula by keeping constant, ignoring that the mechanical restoring torque—and thus the required magnetic deflecting torque—depends on the effective gravity () in the accelerating frame.
By using a gravity-based restoring mechanism, the problem forces the realization that .
Secondary traps involve incorrectly scaling the shunt resistance linearly with (yielding ) or approximating the shunt formula by ignoring the galvanometer current in the denominator (yielding ).
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Moving Charges and Magnetism - Class 12 |
| Concept | Shunt Resistance Conversion |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |