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Question #43032

Difficulty: 8/10 | 🟢 Free

The Question

A galvanometer coil is modeled as a physical pendulum. It has a moment of inertia I=2×10−4 kg m2I = 2 \times 10^{-4} \text{ kg m}^2, a torsional spring constant k=10−2 N m/radk = 10^{-2} \text{ N m/rad}, N=100N = 100 turns, cross-sectional area A=10−3 m2A = 10^{-3} \text{ m}^2, and total electrical resistance R=12 ΩR = 12 \text{ }\Omega. The coil is placed in a uniform radial magnetic field of unknown magnitude BB.

At t=0t=0, the coil is at its equilibrium position (θ=0\theta = 0) and is given an initial angular velocity ω0=10 rad/s\omega_0 = 10 \text{ rad/s}. It swings and comes to instantaneous rest for the first time at an angle θf=1 rad\theta_f = 1 \text{ rad}. The phase space trajectory of the coil is recorded, and the area under the angular velocity versus angle curve (ω\omega vs θ\theta) from θ=0\theta = 0 to θ=1 rad\theta = 1 \text{ rad} is measured to be S=6 rad2/sS = 6 \text{ rad}^2/\text{s}.

Assuming the only non-conservative force acting on the system is the magnetic damping due to the induced current in the closed coil circuit, what is the magnitude of the magnetic field BB?

Options

  • A.

    1.0 \text{ T}

  • B.

    2 T\sqrt{2} \text{ T}

  • C.

    1.2 T\sqrt{1.2} \text{ T}

  • D.

    6 T\sqrt{6} \text{ T}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Galvanometer Sensitivity Logic|Mechanical Energy Conservation|Work-Energy Theorem for Rotation

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Work-Energy Theorem in a non-conservative system with velocity-dependent damping.

Students often fall into the trap of assuming mechanical energy is conserved, ignoring the dissipative work done by the induced currents.

Another common pitfall is incorrectly modeling the non-conservative work by treating the damping force as constant or using an average angular velocity.

The problem requires recognizing that the work done by a velocity-dependent torque τ=−cω\tau = -c\omega is ∫−cωdθ\int -c\omega d\theta, which directly corresponds to the area under the phase space trajectory (ω\omega vs θ\theta curve).

By bridging electromagnetic induction with rigid body dynamics, it rigorously evaluates the student's ability to mathematically model dissipative work.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptGalvanometer Sensitivity Logic
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree