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Question #43021
The Question
A particle of mass and charge moves in an elliptical orbit around a fixed heavy nucleus located at one of the foci. The semi-major axis of the orbit is , its eccentricity is , and the time period of revolution is . What is the time-averaged magnitude of the magnetic field produced by the particle at the location of the nucleus? (Assume all parameters are in standard SI units and is the vacuum permeability)
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Magnetic Field on Axis vs. Center|Kepler’s Second Law (Areal Velocity)
Why This Question Is Tricky
Common Mistakes
This question tests the synthesis of the Biot-Savart Law with Kepler's Second Law (Conservation of Angular Momentum) in a non-circular orbit.
A common trap is for students to treat the elliptical orbit as an equivalent circular current loop and incorrectly guess an effective radius, such as the semi-major axis or semi-minor axis .
This leads to incorrect options like or .
The lethal collision occurs when students fail to realize that the magnetic field varies as while the differential time element varies as .
By applying Kepler's Second Law to substitute , the time integral elegantly transforms into an angle integral of , revealing that the effective radius for the time-averaged magnetic field is exactly the semi-latus rectum .
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Moving Charges and Magnetism - Class 12 |
| Concept | Magnetic Field on Axis vs. Center |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |