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Question #43017

Difficulty: 8/10 | 🟢 Free

The Question

An infinite current slab of thickness 2d2d (spanning −d≤x≤d-d \le x \le d) carries a uniform volume current density J⃗=J0k^\vec{J} = J_0 \hat{k}. A conducting wheel of radius RR (R<dR < d) is placed in the xzxz-plane, centered at the origin. The wheel consists of NN (N≥3N \ge 3) thin radial conducting spokes, each of resistance r0r_0, connected at the center to a perfectly conducting axle and at the edge to a perfectly conducting rim. The wheel is forced to rotate about the yy-axis with a constant angular velocity ω⃗=ωj^\vec{\omega} = \omega \hat{j}. Find the external mechanical power PextP_{ext} required to maintain this rotation. (Ignore self-inductance and friction).

Options

  • A.

    Nμ02J02ω2R618r0\frac{N \mu_0^2 J_0^2 \omega^2 R^6}{18 r_0}

  • B.

    Nμ02J02ω2R68r0\frac{N \mu_0^2 J_0^2 \omega^2 R^6}{8 r_0}

  • C.

    Nμ02J02ω2R69r0\frac{N \mu_0^2 J_0^2 \omega^2 R^6}{9 r_0}

  • D.

    Nμ02J02ω2R632r0\frac{N \mu_0^2 J_0^2 \omega^2 R^6}{32 r_0}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Ampere’s Circuital Law Symmetry|Work-Energy Theorem for Rotation|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the coupling of Ampere's Circuital Law with motional EMF in a spatially varying magnetic field, and the application of the Work-Energy Theorem to equate mechanical driving power to Lorentz drag (Joule heating).

The primary trap lies in assuming a uniform magnetic field or misapplying the standard 12BωR2\frac{1}{2}B\omega R^2 formula.

Students must recognize that BB varies linearly with rr along the spoke (B∝rcos⁡θB \propto r \cos\theta), requiring an ∫r2dr\int r^2 dr integration which yields a factor of 1/31/3.

A secondary trap is incorrectly summing the power across the spokes by ignoring the cos⁡2θ\cos^2\theta geometric averaging over the wheel, which contributes an additional factor of 1/21/2.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptAmpere’s Circuital Law Symmetry
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree