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Question #43005
The Question
Two identical LC circuits, each consisting of a capacitor of capacitance and an inductor of inductance , are placed near each other. The total energy of the system is given by , where are the instantaneous charges on the capacitors, are the currents, and is the mutual inductance between the inductors. At , the currents in both circuits are zero, the charge on the first capacitor is , and the charge on the second capacitor is . What is the maximum charge that will appear on the second capacitor during the subsequent oscillations?
Options
- A.
- B.
- C.
Q_0
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
LC Circuit Oscillations|Phase Constant (Epoch)|Superposition of SHMs
Why This Question Is Tricky
Common Mistakes
This question tests the misapplication of energy conservation and superposition in coupled oscillators.
A common trap is assuming that in a coupled LC system, 100% of the initial energy can eventually transfer to one capacitor, leading students to equate the total initial energy to , yielding the incorrect option .
Another trap is directly adding the normal mode amplitudes () without accounting for the phase constant (epoch) mismatch.
Because the initial conditions excite both normal modes with specific amplitudes, the modes interfere.
The maximum charge is dictated by the time-dependent superposition of these modes, which never perfectly align to localize all energy into the second capacitor.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electromagnetic Induction - Class 12 |
| Concept | LC Circuit Oscillations |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |