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Question #43005

Difficulty: 8/10 | 🟢 Free

The Question

Two identical LC circuits, each consisting of a capacitor of capacitance CC and an inductor of inductance LL, are placed near each other. The total energy of the system is given by E=q122C+q222C+12Li12+12Li22+Mi1i2E = \frac{q_1^2}{2C} + \frac{q_2^2}{2C} + \frac{1}{2} L i_1^2 + \frac{1}{2} L i_2^2 + M i_1 i_2, where q1,q2q_1, q_2 are the instantaneous charges on the capacitors, i1=dq1dt,i2=dq2dti_1 = \frac{dq_1}{dt}, i_2 = \frac{dq_2}{dt} are the currents, and M=0.8LM = 0.8 L is the mutual inductance between the inductors. At t=0t=0, the currents in both circuits are zero, the charge on the first capacitor is q1(0)=Q0q_1(0) = Q_0, and the charge on the second capacitor is q2(0)=Q0/2q_2(0) = Q_0/2. What is the maximum charge that will appear on the second capacitor during the subsequent oscillations?

Options

  • A.

    Q02\frac{Q_0}{\sqrt{2}}

  • B.

    52Q0\frac{\sqrt{5}}{2} Q_0

  • C.

    Q_0

  • D.

    Q02\frac{Q_0}{2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

LC Circuit Oscillations|Phase Constant (Epoch)|Superposition of SHMs

Why This Question Is Tricky

Common Mistakes

This question tests the misapplication of energy conservation and superposition in coupled oscillators.

A common trap is assuming that in a coupled LC system, 100% of the initial energy can eventually transfer to one capacitor, leading students to equate the total initial energy 5Q028C\frac{5Q_0^2}{8C} to qmax22C\frac{q_{max}^2}{2C}, yielding the incorrect option 52Q0\frac{\sqrt{5}}{2}Q_0.

Another trap is directly adding the normal mode amplitudes (0.75Q0+0.25Q0=Q00.75 Q_0 + 0.25 Q_0 = Q_0) without accounting for the phase constant (epoch) mismatch.

Because the initial conditions excite both normal modes with specific amplitudes, the modes interfere.

The maximum charge is dictated by the time-dependent superposition of these modes, which never perfectly align to localize all energy into the second capacitor.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectromagnetic Induction - Class 12
ConceptLC Circuit Oscillations
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree