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Question #43003

Difficulty: 8/10 | 🟢 Free

The Question

A perfectly conducting (superconducting) closed loop of wire has a variable self-inductance given by L(θ)=L0(3+2sin⁡θ)L(\theta) = L_0 (3 + 2\sin\theta), where θ\theta is the angular position of a movable segment of the loop. The movable segment has a moment of inertia JJ about its fixed axis of rotation. Initially, the segment is held at rest at θ=0\theta = 0, and a steady current I0I_0 flows through the loop. The segment is then released. Assuming no mechanical friction and no external magnetic field, what is the maximum angular speed ωmax\omega_{\text{max}} achieved by the movable segment?

Options

  • A.

    I06L05JI_0 \sqrt{\frac{6 L_0}{5 J}}

  • B.

    I02L0JI_0 \sqrt{\frac{2 L_0}{J}}

  • C.

    I012L05JI_0 \sqrt{\frac{12 L_0}{5 J}}

  • D.

    I03L05JI_0 \sqrt{\frac{3 L_0}{5 J}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

LC Circuit Oscillations|Faraday’s Law Vector Form|Flux and Surface Geometry

Why This Question Is Tricky

Common Mistakes

This question tests the misapplication of Faraday's law and Kirchhoff's loop rule in circuits with time-varying inductance.

A common trap is assuming that zero resistance implies Ldidt=0L \frac{di}{dt} = 0, leading students to incorrectly believe the current I0I_0 remains constant.

If they assume constant current, they calculate the work done by the magnetic torque τ=12I2dLdθ\tau = \frac{1}{2}I^2 \frac{dL}{d\theta} as ∫0π/212I02(2L0cos⁡θ)dθ=I02L0\int_0^{\pi/2} \frac{1}{2}I_0^2 (2L_0\cos\theta) d\theta = I_0^2 L_0, yielding an incorrect angular velocity of I02L0/JI_0 \sqrt{2L_0/J} (Option B).

The correct physical principle is that the total magnetic flux Φ=L(θ)I\Phi = L(\theta)I is conserved.

The product rule ddt(Li)=Ldidt+idLdt=0\frac{d}{dt}(L i) = L \frac{di}{dt} + i \frac{dL}{dt} = 0 dictates that the current must decrease as the inductance increases, fundamentally altering the energy transfer.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectromagnetic Induction - Class 12
ConceptLC Circuit Oscillations
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree