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Question #43003
The Question
A perfectly conducting (superconducting) closed loop of wire has a variable self-inductance given by , where is the angular position of a movable segment of the loop. The movable segment has a moment of inertia about its fixed axis of rotation. Initially, the segment is held at rest at , and a steady current flows through the loop. The segment is then released. Assuming no mechanical friction and no external magnetic field, what is the maximum angular speed achieved by the movable segment?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
LC Circuit Oscillations|Faraday’s Law Vector Form|Flux and Surface Geometry
Why This Question Is Tricky
Common Mistakes
This question tests the misapplication of Faraday's law and Kirchhoff's loop rule in circuits with time-varying inductance.
A common trap is assuming that zero resistance implies , leading students to incorrectly believe the current remains constant.
If they assume constant current, they calculate the work done by the magnetic torque as , yielding an incorrect angular velocity of (Option B).
The correct physical principle is that the total magnetic flux is conserved.
The product rule dictates that the current must decrease as the inductance increases, fundamentally altering the energy transfer.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electromagnetic Induction - Class 12 |
| Concept | LC Circuit Oscillations |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |