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Question #42988

Difficulty: 8/10 | 🟢 Free

The Question

A highly flexible, tightly wound solenoid of natural length L0L_0, total number of turns NN, cross-sectional area AA, and total mass MM is suspended vertically from its upper end in a uniform downward gravitational field gg. The solenoid behaves elastically like a helical spring with an overall equivalent spring constant kk. Assuming the cross-sectional area AA remains constant and the solenoid reaches mechanical equilibrium under its own weight, what is the total self-inductance LL of the suspended solenoid? (Ignore end effects and assume μ0\mu_0 is the permeability of free space)

Options

  • A.

    μ0N2AkMgln⁡(1+MgkL0)\frac{\mu_0 N^2 A k}{M g} \ln\left(1 + \frac{M g}{k L_0}\right)

  • B.

    μ0N2AL0+Mg2k\frac{\mu_0 N^2 A}{L_0 + \frac{M g}{2 k}}

  • C.

    μ0N2AL0+Mgk\frac{\mu_0 N^2 A}{L_0 + \frac{M g}{k}}

  • D.

    μ0N2Ak2Mgln⁡(1+2MgkL0)\frac{\mu_0 N^2 A k}{2 M g} \ln\left(1 + \frac{2 M g}{k L_0}\right)

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Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Self-Inductance of Solenoid|Wire Elongation under Self-Weight|Work Done in Stretching

Why This Question Is Tricky

Common Mistakes

This question tests the coupling of elastic mechanics and electromagnetism, specifically targeting the misconception that a non-uniformly stretched solenoid can be modeled using an average turn density or average length.

Students often fall into the trap of calculating the total extension of the center of mass (ΔL=Mg/2k\Delta L = Mg/2k) and substituting the new total length into the standard formula L=μ0N2A/LnewL = \mu_0 N^2 A / L_{new}.

However, inductance depends on the integral of the square of the local turn density n(x)2n(x)^2.

Because the self-weight causes a linearly varying tension, the local strain and turn density vary continuously.

The correct approach requires defining the local inductance differential dL=μ0n(x)2AdxdL = \mu_0 n(x)^2 A dx based on the local stretching dxdx of an unextended element dydy, and integrating over the natural length.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectromagnetic Induction - Class 12
ConceptSelf-Inductance of Solenoid
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree