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Question #42988
The Question
A highly flexible, tightly wound solenoid of natural length , total number of turns , cross-sectional area , and total mass is suspended vertically from its upper end in a uniform downward gravitational field . The solenoid behaves elastically like a helical spring with an overall equivalent spring constant . Assuming the cross-sectional area remains constant and the solenoid reaches mechanical equilibrium under its own weight, what is the total self-inductance of the suspended solenoid? (Ignore end effects and assume is the permeability of free space)
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Self-Inductance of Solenoid|Wire Elongation under Self-Weight|Work Done in Stretching
Why This Question Is Tricky
Common Mistakes
This question tests the coupling of elastic mechanics and electromagnetism, specifically targeting the misconception that a non-uniformly stretched solenoid can be modeled using an average turn density or average length.
Students often fall into the trap of calculating the total extension of the center of mass () and substituting the new total length into the standard formula .
However, inductance depends on the integral of the square of the local turn density .
Because the self-weight causes a linearly varying tension, the local strain and turn density vary continuously.
The correct approach requires defining the local inductance differential based on the local stretching of an unextended element , and integrating over the natural length.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electromagnetic Induction - Class 12 |
| Concept | Self-Inductance of Solenoid |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |