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Question #42944
The Question
A large rectangular tank is completely filled with an uncharged, non-viscous liquid of density . A rigid, smooth, straight insulating rod of length is fixed inside the tank. The tank is subjected to a constant horizontal acceleration to the right. A uniform horizontal electric field of magnitude is established in the space, pointing to the right. Ignore any dielectric effects of the liquid.
A small bead of mass , volume , charge , and density is threaded on the rod. The rod is oriented such that it lies entirely within the vertical plane of acceleration and is parallel to the isobaric surfaces of the liquid, with its higher end on the left.
The bead is released from rest from the higher end of the rod. Given that (where is the acceleration due to gravity), what is the kinetic energy of the bead when it reaches the lower end of the rod?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Potential Gradient Direction|Conservative Field Path Independence|Accelerated Frame Hydrostatics
Why This Question Is Tricky
Common Mistakes
This question tests the superposition of inertial, gravitational, and electrostatic fields, specifically focusing on the boundary condition mismatch in an accelerated fluid.
Students often fall into the trap of either ignoring the pseudo force on the bead itself (focusing only on the fluid's tilt) or calculating buoyancy using standard gravity () instead of the effective gravity field ().
The correct approach requires treating the potential gradient as a vector sum and projecting the true net force onto the modified equipotential (isobaric) surface of the fluid.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electrostatic Potential and Capacitance - Class 12 |
| Concept | Potential Gradient Direction |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |