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Question #42939

Difficulty: 8/10 | 🟢 Free

The Question

A particle of mass mm and charge qq is constrained to move along a smooth quarter-circular track of radius RR in the xyxy-plane, from point A(R,0)A(R, 0) to point B(0,R)B(0, R). The region contains a viscous fluid that exerts a drag force on the particle given by F⃗d=−m2Rv2v^\vec{F}_d = -\frac{m}{2R} v^2 \hat{v}, where vv is the instantaneous speed and v^\hat{v} is the unit vector in the direction of velocity. A uniform electrostatic field E⃗=E0j^\vec{E} = E_0 \hat{j} exists in the region. If the particle is projected from point AA with an initial kinetic energy K0K_0, what is its kinetic energy upon reaching point BB? (Assume gravity is negligible).

Options

  • A.

    K0e−π/2+qE0R2(1−e−π/2)K_0 e^{-\pi/2} + \frac{q E_0 R}{2} \left( 1 - e^{-\pi/2} \right)

  • B.

    K0+qE0RK_0 + q E_0 R

  • C.

    K0(1−π2)+qE0RK_0 \left( 1 - \frac{\pi}{2} \right) + q E_0 R

  • D.

    K0eπ/2+qE0R2(1+eπ/2)K_0 e^{\pi/2} + \frac{q E_0 R}{2} \left( 1 + e^{\pi/2} \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Conservative Field Path Independence|Work-Energy Theorem Validity|Conservative Force Field

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Work-Energy Theorem in the presence of both conservative and non-conservative, path-dependent forces.

A common trap for students is to blindly apply the conservation of mechanical energy (ΔK+ΔU=0\Delta K + \Delta U = 0) because they see an electrostatic field, completely ignoring the non-conservative drag force (Option B).

Even if they recognize the drag force, they might incorrectly assume it does constant work or fail to set up the differential equation linking kinetic energy to the path variable θ\theta.

By making the drag force proportional to v2v^2, the work done by drag becomes directly proportional to the instantaneous kinetic energy, forcing the student to abandon simple algebraic shortcuts and solve a first-order linear differential equation to find the final kinetic energy.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptConservative Field Path Independence
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree