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Question #42938

Difficulty: 8/10 | 🟢 Free

The Question

A closed insulating vertical cylinder of height HH is fixed inside an elevator that is accelerating upwards with a constant acceleration a=ga = g. The cylinder contains a fluid of total mass MM and total charge QQ. The charge is permanently bound to the fluid particles such that the local charge density is always proportional to the local mass density. Initially, the fluid is in a state where its mass density increases linearly with height yy (measured from the bottom of the cylinder): ρm(y)=cy\rho_m(y) = c y, where cc is a constant. An external non-uniform electric field is maintained inside the cylinder, given by E⃗=E0(1−yH)j^\vec{E} = E_0 \left(1 - \frac{y}{H}\right) \hat{j}, where j^\hat{j} is the unit vector in the upward vertical direction relative to the elevator. Over time, the fluid spontaneously redistributes itself to achieve a uniform mass density throughout the cylinder. If this redistribution process occurs such that the net change in the total potential energy (gravitational + electrostatic) of the fluid in the frame of the elevator is zero, what is the required value of E0E_0?

Options

  • A.

    4MgQ\frac{4Mg}{Q}

  • B.

    24Mg5Q\frac{24Mg}{5Q}

  • C.

    2MgQ\frac{2Mg}{Q}

  • D.

    12Mg5Q\frac{12Mg}{5Q}

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Conservative Field Path Independence|Gravitational Potential Energy (System)|Frame of Reference

Why This Question Is Tricky

Common Mistakes

This question tests the calculation of potential energy for continuous mass and charge distributions in non-uniform fields and non-inertial frames.

The primary trap lies in the electrostatic potential energy calculation: students often incorrectly assume that UeU_e can be evaluated by placing the total charge at the center of mass (COM), i.e., Ue=QV(ycm)U_e = Q V(y_{cm}).

While this shortcut works for uniform fields (like standard gravity), it fails in non-uniform fields where rigorous integration ∫V(y)dq\int V(y) dq is mandatory.

Additionally, students may forget to apply the pseudo-force in the accelerating elevator frame, missing the effective gravity geff=2gg_{eff} = 2g.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptConservative Field Path Independence
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree