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Question #42930

Difficulty: 8/10 | 🟢 Free

The Question

A solid non-conducting sphere of radius RR has a uniform volume charge density and carries a total positive charge QQ. The electric potential is defined to be zero at the center of the sphere. A particle of mass mm and charge −q-q (where q>0q > 0) is performing uniform circular motion around the sphere at an orbital radius r=2Rr = 2R. What is the total mechanical energy of the particle? (Assume the permittivity of free space is ϵ0\epsilon_0 and ignore gravity)

Options

  • A.

    5qQ16πϵ0R\frac{5qQ}{16\pi\epsilon_0 R}

  • B.

    −qQ16πϵ0R-\frac{qQ}{16\pi\epsilon_0 R}

  • C.

    3qQ16πϵ0R\frac{3qQ}{16\pi\epsilon_0 R}

  • D.

    −3qQ16πϵ0R-\frac{3qQ}{16\pi\epsilon_0 R}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Non-conducting Charged Sphere|Reference Potential Convention|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's fundamental understanding of the electric potential as a line integral of the electric field, specifically challenging the rote memorization of the standard potential formula V=kQ/rV = kQ/r.

By shifting the zero-potential reference point to the center of the non-conducting sphere, students cannot simply use the standard formula.

They must correctly integrate the linear interior electric field from r=0r=0 to r=Rr=R, and the inverse-square exterior field from r=Rr=R to r=2Rr=2R.

Common traps include defaulting to the standard reference at infinity (yielding −qQ/16πϵ0R-qQ/16\pi\epsilon_0 R), incorrectly setting the surface potential to zero, or mishandling the sign of the test charge when calculating potential energy.

The positive total energy for a bound orbit further challenges students who rely on the heuristic that bound states must have negative total energy, which is only true when U(∞)=0U(\infty) = 0.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectric Charges and Fields - Class 12
ConceptNon-conducting Charged Sphere
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree