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Question #42911
The Question
A non-conducting disc of radius has a non-uniform areal mass density and a non-uniform surface charge density , where is the radial distance from the center. The total mass of the disc is and its total charge is . The disc is initially at rest and is free to rotate about its fixed central axis. A uniform magnetic field, perpendicular to the plane of the disc, is switched on and increases from to . Neglecting any friction or radiation losses, what is the final angular velocity of the disc?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Continuous Charge Distribution|Angular Momentum conservation|Magnetic Dipole Moment of Revolving Electron|Vector Cross-Product
Why This Question Is Tricky
Common Mistakes
This question tests the rigorous application of Faraday's Law and rotational mechanics against the common heuristic of the gyromagnetic ratio.
Students frequently fall into the trap of assuming the gyromagnetic ratio applies universally, leading them to directly apply the uniform disc formula .
By introducing decoupled, non-uniform mass and charge distributions, the problem invalidates this shortcut.
The 'lethal' trap lies in failing to independently integrate the induced torque (which depends heavily on the outer radii due to the dependence) and the moment of inertia.
If a student assumes uniform distributions or blindly applies Larmor precession concepts, they will confidently select the incorrect option.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electric Charges and Fields - Class 12 |
| Concept | Continuous Charge Distribution |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |