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Question #42872

Difficulty: 8/10 | 🟢 Free

The Question

A small block of mass m=1 kgm = 1 \text{ kg} is placed on a long horizontal plank of mass M=3 kgM = 3 \text{ kg}. The plank is attached to a fixed wall by a horizontal ideal spring of force constant k=400 N/mk = 400 \text{ N/m}. The coefficient of static friction between the block and the plank is μs=32\mu_s = \frac{\sqrt{3}}{2}. The plank rests on a frictionless horizontal floor. Let x=0x=0 be the equilibrium position of the plank. At t=0t = 0, the plank is at x=−0.05 mx = -0.05 \text{ m} and is moving with a velocity v=−32 m/sv = -\frac{\sqrt{3}}{2} \text{ m/s}. Assuming the block does not slip on the plank initially, find the exact time tt at which the block first begins to slip. (Take g=10 m/s2g = 10 \text{ m/s}^2)

Options

  • A.

    π60 s\frac{\pi}{60} \text{ s}

  • B.

    π20 s\frac{\pi}{20} \text{ s}

  • C.

    π30 s\frac{\pi}{30} \text{ s}

  • D.

    π12 s\frac{\pi}{12} \text{ s}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Phase Constant (Epoch)|Simple Pendulum Small Angle Approximation|Static Friction Threshold

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to synthesize SHM kinematics with non-constant restorative forces and static friction thresholds.

The primary trap lies in the phase constant determination: students often ignore the negative sign of the initial velocity, incorrectly assuming the block is moving towards the mean position.

This yields a false phase and leads directly to the distractor t=π/20t = \pi/20 s.

Additionally, students may misidentify the slipping condition by equating the spring force directly to the friction on the block (kx=μsmgkx = \mu_s mg) instead of using the correct pseudo-force/acceleration relation (mω2x=μsmgm\omega^2 x = \mu_s mg), or they might assume slipping only occurs exactly at the extreme amplitude, leading to the distractor t=π/30t = \pi/30 s.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWaves - Class 11 Part 2
ConceptPhase Constant (Epoch)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree