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Question #42870

Difficulty: 8/10 | 🟢 Free

The Question

A sound source S1S_1 and a stationary observer OO are situated in a horizontal plane. S1S_1 moves on a circular track of radius RR centered at the origin (0,0)(0,0). The observer OO is located at a distance LL from the origin along the +x+x-axis, where L≫RL \gg R. At t=0t=0, S1S_1 starts from rest at (R,0)(R,0) and moves counterclockwise with a constant angular acceleration α\alpha. S1S_1 continuously emits sound of frequency f0f_0. A stationary source S2S_2 located at the origin also emits sound of frequency f0f_0. The speed of sound in air is cc (assume c≫Rαc \gg R\sqrt{\alpha}). Find the average beat frequency recorded by the observer OO during the time interval corresponding to the first complete revolution of S1S_1.

Options

  • A.

    2f0Rcαπ\frac{2 f_0 R}{c} \sqrt{\frac{\alpha}{\pi}}

  • B.

    πf0Rcαπ\frac{\pi f_0 R}{c} \sqrt{\frac{\alpha}{\pi}}

  • C.

    4f0Rcαπ\frac{4 f_0 R}{c} \sqrt{\frac{\alpha}{\pi}}

  • D.

    f0Rcαπ\frac{f_0 R}{c} \sqrt{\frac{\alpha}{\pi}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Beats and Frequency Difference|Non-Uniform Circular Motion|Mean vs RMS Values

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Doppler effect in non-uniform circular motion and the rigorous definition of average values.

A common trap is assuming that the average beat frequency is proportional to the average speed of the source (⟨v⟩=Rπα\langle v \rangle = R\sqrt{\pi\alpha}), which incorrectly yields Option B.

Students must recognize that the instantaneous beat frequency is a non-linear function of time, requiring integration of the absolute frequency difference over the period.

The physical elegance of the problem lies in the transformation vdt=Rdθv dt = R d\theta, which shows that the total number of beats depends only on the total distance covered along the line of sight (4R4R), independent of the angular acceleration.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWaves - Class 11 Part 2
ConceptBeats and Frequency Difference
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree