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Question #42867

Difficulty: 8/10 | 🟢 Free

The Question

An observer is stationary at the origin (0,0)(0,0) of a Cartesian coordinate system. At time t=0t = 0, two identical sound sources, S1S_1 and S2S_2, are located at a height H=110 mH = 110 \text{ m} on the y-axis (initial position (0,110 m)(0, 110 \text{ m})). Source S1S_1 is projected horizontally with a velocity u⃗1=10i^ m/s\vec{u}_1 = 10 \hat{i} \text{ m/s}. Source S2S_2 is simultaneously dropped from rest. Both sources continuously emit sound of proper frequency f0=1215 Hzf_0 = 1215 \text{ Hz}. The speed of sound in air is vs=340 m/sv_s = 340 \text{ m/s}, and the acceleration due to gravity is g=10 m/s2g = 10 \text{ m/s}^2 (acting in the −j^-\hat{j} direction). Calculate the beat frequency detected by the observer corresponding to the sound waves emitted by the sources at the exact instant t=4 st = 4 \text{ s}.

Options

  • A.

    102 \text{ Hz}

  • B.

    0 \text{ Hz}

  • C.

    36 \text{ Hz}

  • D.

    54 \text{ Hz}

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Beats and Frequency Difference|Relative Velocity in 2D|Projectile Path Equation

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly apply the Doppler effect in two-dimensional kinematics.

The primary trap lies in calculating the effective source velocity.

Students frequently misapply the Doppler formula by using either the absolute speed of the projectile (∣v⃗∣|\vec{v}|) or merely its vertical velocity component (vyv_y), ignoring the geometric relationship between the source and the observer.

The correct physical principle requires projecting the instantaneous velocity vector onto the line-of-sight unit vector connecting the source to the observer (v⃗⋅n^\vec{v} \cdot \hat{n}).

By setting up a parabolic trajectory, the problem forces a rigorous vector dot product to find the true radial velocity (v∥=16 m/sv_{\parallel} = 16 \text{ m/s}), distinguishing it from the trivial 1D free-fall case of the second source.

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Question Information

SubjectPhysics
ChapterWaves - Class 11 Part 2
ConceptBeats and Frequency Difference
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree