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Question #42844

Difficulty: 8/10 | 🟢 Free

The Question

An elevator is accelerating vertically upwards with a constant acceleration aa. Inside the elevator, an infinite flat non-conducting sheet with a uniform positive surface charge density σ\sigma is fixed vertically. A rigid, rough, non-conducting vertical rod is fixed parallel to the sheet at a distance dd from it. A bead of mass mm and positive charge qq is threaded on the rod. The coefficient of kinetic friction between the bead and the rod is μ\mu. If the bead is released from rest relative to the elevator, what is its kinetic energy relative to the elevator after it has slid a distance LL down the rod? (Assume m(g+a)>μqσ2ε0m(g+a) > \frac{\mu q \sigma}{2\varepsilon_0} and neglect edge effects).

Options

  • A.

    (m(g+a)−μqσ2ε0)L\left( m(g+a) - \frac{\mu q \sigma}{2\varepsilon_0} \right) L

  • B.

    (mg−μqσ2ε0)L\left( mg - \frac{\mu q \sigma}{2\varepsilon_0} \right) L

  • C.

    (m(g−a)−μqσ2ε0)L\left( m(g-a) - \frac{\mu q \sigma}{2\varepsilon_0} \right) L

  • D.

    (m(g+a)+qσ2ε0)L\left( m(g+a) + \frac{q \sigma}{2\varepsilon_0} \right) L

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Field due to Infinite Sheet|Work-Energy Theorem Validity|Frame of Reference

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Work-Energy Theorem in a non-inertial reference frame combined with electrostatics.

The primary trap is the 'Standard Intuition' where students either calculate the work done using only the ground-frame forces (ignoring the pseudo-force −ma-ma which does real work in the elevator frame) or incorrectly assume the electric field does work despite the displacement being parallel to the equipotential surface (the sheet).

By forcing the analysis into the accelerating frame, students must recognize that the effective gravity is (g+a)(g+a) downwards, while the electric field solely contributes to the normal force and subsequent non-conservative frictional work.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectric Charges and Fields - Class 12
ConceptField due to Infinite Sheet
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree