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Question #42835

Difficulty: 8/10 | 🟢 Free

The Question

A non-conducting thin disc of radius RR has a surface charge density σ(r)=σ0(1−rR)\sigma(r) = \sigma_0 \left(1 - \frac{r}{R}\right), where rr is the radial distance from the center and σ0\sigma_0 is a positive constant. The disc rotates with a constant angular velocity ω\omega about its central geometric axis. The disc is placed entirely inside a long ideal solenoid such that the axis of rotation of the disc is perpendicular to the central axis of the solenoid. The solenoid has nn turns per unit length and is wound using a wire of cross-sectional area SS. The wire material has a free electron number density η\eta. Due to Joule heating, the temperature TT of the solenoid wire increases, causing the drift velocity of the free electrons to vary as vd(T)=v0e−αTv_d(T) = v_0 e^{-\alpha T}, where v0v_0 and α\alpha are positive constants. Assuming the external magnetic field is uniform over the disc, what is the magnitude of the magnetic torque τ\tau acting on the disc at temperature TT?

Options

  • A.

    πμ0σ0ωR4nηeSv0e−αT20\frac{\pi \mu_0 \sigma_0 \omega R^4 n \eta e S v_0 e^{-\alpha T}}{20}

  • B.

    πμ0σ0ωR4nηeSv0e−αT12\frac{\pi \mu_0 \sigma_0 \omega R^4 n \eta e S v_0 e^{-\alpha T}}{12}

  • C.

    πμ0σ0ωR4nηeSv0e−αT6\frac{\pi \mu_0 \sigma_0 \omega R^4 n \eta e S v_0 e^{-\alpha T}}{6}

  • D.

    πμ0σ0ωR4nηeSv0e−αT10\frac{\pi \mu_0 \sigma_0 \omega R^4 n \eta e S v_0 e^{-\alpha T}}{10}

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Continuous Charge Distribution|Torque on Current Loop|Drift Velocity Mechanism

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to synthesize electromagnetism concepts across different scales and distributions.

The primary trap lies in the calculation of the magnetic dipole moment for a non-uniform continuous charge distribution.

Students frequently misapply the formula μ=12QωR2\mu = \frac{1}{2} Q \omega R^2 (valid only for a ring) or μ=14QωR2\mu = \frac{1}{4} Q \omega R^2 (valid only for a uniform disc).

By forcing an integration over σ(r)=σ0(1−r/R)\sigma(r) = \sigma_0(1 - r/R), the problem exposes reliance on memorized discrete formulas (leading to incorrect denominators like 12 or 6).

Furthermore, the question couples this with the microscopic drift velocity model (I=neeAvdI = n_e e A v_d) to determine the external magnetic field, testing whether students can correctly link temperature-dependent microscopic electron motion to macroscopic magnetic torque.

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Question Information

SubjectPhysics
ChapterElectric Charges and Fields - Class 12
ConceptContinuous Charge Distribution
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree