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Question #42833

Difficulty: 8/10 | 🟢 Free

The Question

A non-conducting solid sphere of initial radius R0R_0 has a radially varying mass density ρm(r)\rho_m(r). The moment of inertia of the spherical region enclosed within any radius rr (about a diametric axis) is given by I(r)=I0(rR0)6I(r) = I_0 \left(\frac{r}{R_0}\right)^6, where I0I_0 is the total initial moment of inertia of the sphere. The sphere carries a total charge QQ, distributed such that the volume charge density is ρe(r)=βρm(r)r2\rho_e(r) = \beta \rho_m(r) r^2, where β\beta is a positive constant. The sphere is then heated, increasing its temperature by ΔT\Delta T. The coefficient of linear thermal expansion of the material is α\alpha. Assuming the charge is bound to the material and αΔT≪1\alpha \Delta T \ll 1, what is the magnitude of the electric field at a fixed spatial distance r=R0/2r = R_0/2 from the center of the sphere?

Options

  • A.

    Q64πϵ0R02(1−6αΔT)\frac{Q}{64\pi \epsilon_0 R_0^2} (1 - 6\alpha \Delta T)

  • B.

    Q64πϵ0R02(1−2αΔT)\frac{Q}{64\pi \epsilon_0 R_0^2} (1 - 2\alpha \Delta T)

  • C.

    Q64πϵ0R02(1−3αΔT)\frac{Q}{64\pi \epsilon_0 R_0^2} (1 - 3\alpha \Delta T)

  • D.

    Q64πϵ0R02(1+6αΔT)\frac{Q}{64\pi \epsilon_0 R_0^2} (1 + 6\alpha \Delta T)

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Correct Answer

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Continuous Charge Distribution|Moment of Inertia (MOI) Symmetry|Variation of Density with Temperature

Why This Question Is Tricky

Common Mistakes

This question tests the integration of Gauss's Law with a thermally expanding, non-uniform charge distribution.

The primary trap is failing to distinguish between a fixed spatial coordinate and a co-moving material coordinate.

Students often incorrectly calculate the electric field at the expanded material point (yielding the 1−2αΔT1-2\alpha \Delta T trap) or incorrectly apply the volume expansion factor directly to the charge density (yielding the 1−3αΔT1-3\alpha \Delta T trap).

Furthermore, it requires recognizing the mathematical symmetry between the moment of inertia integral and the charge distribution integral to bypass the unknown mass density function.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectric Charges and Fields - Class 12
ConceptContinuous Charge Distribution
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree