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Question #42823

Difficulty: 8/10 | 🟢 Free

The Question

A gas of Hydrogen atoms is placed in a uniform external electric field E⃗=E0k^\vec{E} = E_0 \hat{k}. The first-order Stark effect perturbs the first excited state (n=2n=2), splitting the degenerate manifold into three distinct energy levels: E2(0)E_2^{(0)}, E2(0)+3ea0E0E_2^{(0)} + 3ea_0E_0, and E2(0)−3ea0E0E_2^{(0)} - 3ea_0E_0, where E2(0)E_2^{(0)} is the unperturbed energy, ee is the elementary charge, and a0a_0 is the Bohr radius. The ground state (1s1s) energy E1(0)E_1^{(0)} remains unshifted. The states corresponding to the shifted energies E2(0)±3ea0E0E_2^{(0)} \pm 3ea_0E_0 are linear combinations of the 2s2s and 2pz2p_z orbitals, while the unshifted energy E2(0)E_2^{(0)} corresponds to the 2px2p_x and 2py2p_y orbitals. Let λ0\lambda_0 be the wavelength of the Lyman-α\alpha line in the absence of the electric field. Assuming 3ea0E0≪(E2(0)−E1(0))3ea_0E_0 \ll (E_2^{(0)} - E_1^{(0)}), what is the number of allowed distinct spectral lines observed for transitions from the n=2n=2 manifold to the ground state, and what is the maximum difference in wavelength Δλ\Delta \lambda between the highest and lowest energy photons emitted?

Options

  • A.

    3 lines, 6ea0E0λ02hc\frac{6ea_0E_0 \lambda_0^2}{hc}

  • B.

    2 lines, 3ea0E0λ02hc\frac{3ea_0E_0 \lambda_0^2}{hc}

  • C.

    3 lines, 3ea0E0λ02hc\frac{3ea_0E_0 \lambda_0^2}{hc}

  • D.

    1 line, 00

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Superposition Principle|Energy Level Scaling|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the superposition principle in quantum states under an external electric field perturbation (Stark effect).

A common trap is for students to rigidly apply the unperturbed dipole selection rule (Δl=±1\Delta l = \pm 1) and assume that one of the shifted states must be pure 2s2s (forbidden) and the other pure 2pz2p_z (allowed), leading to an incorrect count of 2 spectral lines.

In reality, the external field breaks spherical symmetry, mixing the parity states so that both shifted levels are linear combinations of 2s2s and 2pz2p_z.

Consequently, both states acquire a non-zero dipole transition matrix element to the 1s1s state, resulting in 3 distinct spectral lines.

Another trap is treating the external field as a global potential shift, which would incorrectly yield 1 line with zero wavelength shift.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectric Charges and Fields - Class 12
ConceptSuperposition Principle
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree