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Question #42805

Difficulty: 8/10 | 🟢 Free

The Question

A particle of mass mm and charge +q+q is attached to the lower end of a massless spring of spring constant kk. The upper end of the spring is fixed to a rigid support. The system is initially at rest in its vertical equilibrium position under gravity. At t=0t = 0, a time-varying vertical electric field E(t)=E0sin⁡(ωt)E(t) = E_0 \sin(\omega t) is switched on, pointing downwards. Given that the angular frequency of the electric field is ω=12km\omega = \frac{1}{2} \sqrt{\frac{k}{m}}, what is the total mechanical energy of the oscillator (sum of kinetic, elastic potential, and gravitational potential energies) at time t=πωt = \frac{\pi}{\omega}, relative to its initial equilibrium state at t=0t=0?

Options

  • A.

    8q2E029k\frac{8 q^2 E_0^2}{9 k}

  • B.

    00

  • C.

    q2E022k\frac{q^2 E_0^2}{2 k}

  • D.

    2q2E023k\frac{2 q^2 E_0^2}{3 k}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Work against Conservative Force|Vertical Oscillations|Vector Calculus

Why This Question Is Tricky

Common Mistakes

This question tests the misapplication of energy conservation in time-varying fields.

Students often incorrectly assume that because the electrostatic force is conservative at any given instant, they can define a time-dependent potential energy UE(t)=−qE(t)yU_E(t) = -qE(t)y and conserve the total energy Emech+UE=constantE_{mech} + U_E = \text{constant}.

Since E(π/ω)=0E(\pi/\omega) = 0 and y(π/ω)=0y(\pi/\omega) = 0, this flawed logic leads to the conclusion that ΔEmech=0\Delta E_{mech} = 0.

However, the Hamiltonian of the system explicitly depends on time, meaning total mechanical energy is not conserved; the electric field does net work on the oscillator over the half-cycle, which must be calculated via the Work-Energy Theorem or by explicitly solving the non-autonomous differential equation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptWork against Conservative Force
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree