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Question #42796

Difficulty: 8/10 | 🟢 Free

The Question

A long cylindrical region of radius RR contains a spatially uniform magnetic field B⃗=αtk^\vec{B} = \alpha t \hat{k}, where α\alpha is a positive constant, tt is time, and k^\hat{k} is the unit vector along the z-axis. An infinitely long straight wire carrying a uniform linear charge density λ\lambda is fixed along the z-axis. A point charge qq is moved from point AA with cylindrical coordinates (a,0,0)(a, 0, 0) to point BB with coordinates (b,π/2,0)(b, \pi/2, 0), where a<b<Ra < b < R. The charge is first moved radially outward from r=ar=a to r=br=b at θ=0\theta=0, and then moved along a circular arc of constant radius bb from θ=0\theta=0 to θ=π/2\theta=\pi/2. What is the total work done by the net electric field on the point charge qq during this entire process?

Options

  • A.

    qλ2πϵ0ln⁡(ba)−πqαb24\frac{q\lambda}{2\pi\epsilon_0} \ln\left(\frac{b}{a}\right) - \frac{\pi q \alpha b^2}{4}

  • B.

    qλ2πϵ0ln⁡(ba)\frac{q\lambda}{2\pi\epsilon_0} \ln\left(\frac{b}{a}\right)

  • C.

    qλ2πϵ0ln⁡(ba)−πqαa24\frac{q\lambda}{2\pi\epsilon_0} \ln\left(\frac{b}{a}\right) - \frac{\pi q \alpha a^2}{4}

  • D.

    qλ2πϵ0ln⁡(ba)+πqαb24\frac{q\lambda}{2\pi\epsilon_0} \ln\left(\frac{b}{a}\right) + \frac{\pi q \alpha b^2}{4}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Potential of Concentric Shells|Work against Conservative Force|Induced Electric Fields

Why This Question Is Tricky

Common Mistakes

This question tests the critical distinction between conservative electrostatic fields and non-conservative induced electric fields.

Students commonly fall into the trap of treating all electric work as path-independent (W=−qΔVW = -q\Delta V), calculating only the electrostatic potential difference and completely ignoring the induced EMF (Option B).

By explicitly specifying a two-part path, the problem forces the evaluation of the line integral ∫E⃗ind⋅dl⃗\int \vec{E}_{ind} \cdot d\vec{l}, highlighting that work done by a time-varying magnetic field is strictly path-dependent.

Option C traps students who incorrectly use the initial radius 'a' for the arc, and Option D traps those who make a sign error applying Lenz's Law.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptPotential of Concentric Shells
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree