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Question #42791

Difficulty: 8/10 | 🟢 Free

The Question

A solid non-conducting sphere of radius RR has a non-uniform volume charge density given by ρ(r)=ρ0(1−rR)\rho(r) = \rho_0 \left(1 - \frac{r}{R}\right), where rr is the radial distance from the center of the sphere. A spherical cavity of radius R/2R/2, centered at a distance R/2R/2 from the center of the original sphere, is completely hollowed out. A point test charge qq is placed exactly at the center of the original sphere. What is the magnitude of the net electric force experienced by the test charge?

Options

  • A.

    5qρ0R48ϵ0\frac{5 q \rho_0 R}{48 \epsilon_0}

  • B.

    qρ0R12ϵ0\frac{q \rho_0 R}{12 \epsilon_0}

  • C.

    qρ0R6ϵ0\frac{q \rho_0 R}{6 \epsilon_0}

  • D.

    qρ0R15ϵ0\frac{q \rho_0 R}{15 \epsilon_0}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Symmetry and Virtual Work|Gravitational Potential Reference|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the misapplication of Gauss's Law and the uniform cavity theorem (E⃗=ρ3ϵ0a⃗\vec{E} = \frac{\rho}{3\epsilon_0}\vec{a}).

Students reflexively assume that the electric field inside any spherical cavity is uniform and depends only on the density at the cavity's center or the origin, leading to incorrect answers like qρ0R12ϵ0\frac{q \rho_0 R}{12 \epsilon_0} or qρ0R6ϵ0\frac{q \rho_0 R}{6 \epsilon_0}.

However, because the original charge distribution ρ(r)\rho(r) is non-uniform, the removed charge lacks the necessary symmetry for the standard shell theorem to apply.

To solve this, one must use the principle of virtual work (or direct potential gradient integration), setting up the integral in spherical coordinates from the origin to the cavity's boundary r=Rcos⁡θr = R\cos\theta.

Failing to account for the variable density within the integration limits exposes a fundamental misunderstanding of when symmetry-based shortcuts are valid.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptSymmetry and Virtual Work
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree