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Question #42782

Difficulty: 8/10 | 🟢 Free

The Question

Two identical capacitors, each of capacitance CC, are provided. One is initially charged to a potential difference V0V_0, while the other is uncharged. At t=0t=0, they are connected in a closed series loop through a resistor. The resistor is thermally insulated from its surroundings. Its resistance RR increases with the total heat energy HH dissipated in it according to the relation R(H)=R0(1+HU0)R(H) = R_0 \left(1 + \frac{H}{U_0}\right), where R0R_0 is the initial resistance and U0=12CV02U_0 = \frac{1}{2} C V_0^2 is the initial energy stored in the charged capacitor. Assuming the connecting wires have zero resistance and zero heat capacity, find the time tt at which the potential difference across the initially charged capacitor drops to 3V04\frac{3V_0}{4}.

Options

  • A.

    332R0C(8ln⁡2−1)\frac{3}{32} R_0 C (8 \ln 2 - 1)

  • B.

    12R0Cln⁡2\frac{1}{2} R_0 C \ln 2

  • C.

    316R0C(4ln⁡2−1)\frac{3}{16} R_0 C (4 \ln 2 - 1)

  • D.

    18R0C(6ln⁡2+1)\frac{1}{8} R_0 C (6 \ln 2 + 1)

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Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Common Potential Redistribution|Ohm's Law Validity|Approximations

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to integrate Thermodynamics with Electrodynamics, specifically targeting the misapplication of standard RC circuit formulas.

Students commonly fall into the trap of assuming a standard exponential decay V(t)=V0e−t/τV(t) = V_0 e^{-t/\tau} (Option B), ignoring the fact that Joule heating dynamically alters the resistance.

The 'Lethal Collision' occurs because the differential equation dV/dt=−V/(R(T)Ceq)dV/dt = -V/(R(T)C_{eq}) appears intractable if time is kept as the independent variable.

The conceptual breakthrough requires recognizing that heat dissipation H=∫VdqH = \int V dq is path-independent with respect to time, allowing resistance to be expressed purely as a function of the transferred charge qq.

This transforms a complex time-coupled thermal runaway problem into a solvable state-dependent integral.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptCommon Potential Redistribution
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree