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Question #42777

Difficulty: 8/10 | 🟢 Free

The Question

A parallel plate capacitor consists of two circular plates of radius RR separated by a distance dd (d≪Rd \ll R). The space between the plates is filled with a non-magnetic dielectric material whose relative permittivity varies radially as K(r)=1+αrK(r) = 1 + \alpha r, where rr is the distance from the central axis of the plates and α\alpha is a positive constant. A time-varying potential difference V(t)=βtV(t) = \beta t (where β>0\beta > 0 is a constant) is applied across the plates. Neglecting edge effects, what is the magnitude of the Poynting vector S⃗\vec{S} at the edge of the capacitor (r=Rr = R) at time tt?

Options

  • A.

    ε0β2td2(R2+αR22)\varepsilon_0 \frac{\beta^2 t}{d^2} \left( \frac{R}{2} + \frac{\alpha R^2}{2} \right)

  • B.

    ε0β2td2(R2+αR24)\varepsilon_0 \frac{\beta^2 t}{d^2} \left( \frac{R}{2} + \frac{\alpha R^2}{4} \right)

  • C.

    ε0β2td2(R2+αR23)\varepsilon_0 \frac{\beta^2 t}{d^2} \left( \frac{R}{2} + \frac{\alpha R^2}{3} \right)

  • D.

    ε0β2td2(1+αR)R\varepsilon_0 \frac{\beta^2 t}{d^2} (1 + \alpha R) R

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Energy Density Locality|Poynting Vector and Intensity|Medium Dependency

Why This Question Is Tricky

Common Mistakes

This question tests the student's understanding of the Poynting vector and displacement current in a spatially inhomogeneous medium.

A common lethal trap is treating the capacitor as a lumped parameter and assuming the magnetic field at the edge can be calculated using the local displacement current density Jd(R)J_d(R) as if it were uniform (B=μ0Jd(R)R/2B = \mu_0 J_d(R) R / 2), which leads to Option A.

Another trap is incorrectly averaging the dielectric constant linearly without the proper 2πrdr2\pi r dr area weighting, leading to Option B.

Students must recognize that the non-uniform dielectric forces an integration of the local displacement current density over the entire circular area to satisfy the boundary conditions for the global power flow.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptEnergy Density Locality
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree