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Question #42776

Difficulty: 8/10 | 🟢 Free

The Question

A uniform plane electromagnetic wave propagates along the +z+z-direction in a homogeneous, non-magnetic, lossy dielectric medium. The electric field of the wave is given by E⃗(z,t)=E0cos⁡(ωt−kz)i^\vec{E}(z,t) = E_0 \cos(\omega t - kz) \hat{i}, where E0=200 V/mE_0 = 200 \text{ V/m} and ω=108 rad/s\omega = 10^8 \text{ rad/s}. Due to the finite relaxation time of the medium, the dielectric polarization P⃗\vec{P} lags behind the electric field by a phase angle δ=π/6 rad\delta = \pi/6 \text{ rad}, and is given by P⃗(z,t)=P0cos⁡(ωt−kz−δ)i^\vec{P}(z,t) = P_0 \cos(\omega t - kz - \delta) \hat{i}, where P0=10−8 C/m2P_0 = 10^{-8} \text{ C/m}^2. Assuming no free currents exist in the medium, what is the magnitude of the spatial attenuation rate of the time-averaged Poynting vector, ∣∂⟨Sz⟩∂z∣\left| \frac{\partial \langle S_z \rangle}{\partial z} \right|, in the medium?

Options

  • A.

    50 W/m350 \text{ W/m}^3

  • B.

    503 W/m350\sqrt{3} \text{ W/m}^3

  • C.

    100 W/m3100 \text{ W/m}^3

  • D.

    0 W/m30 \text{ W/m}^3

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Dielectric Polarization Logic|Poynting Vector and Intensity|Medium Dependency

Why This Question Is Tricky

Common Mistakes

Students often incorrectly assume that energy dissipation in an electromagnetic wave only occurs via free currents (Ohmic loss, J⃗f⋅E⃗\vec{J}_f \cdot \vec{E}), leading them to conclude that a dielectric without free charge is lossless (0 W/m30 \text{ W/m}^3).

This question tests the understanding that a time-varying polarization P⃗\vec{P} acts as a bound current J⃗p=∂P⃗/∂t\vec{J}_p = \partial\vec{P}/\partial t.

Furthermore, it highlights that the phase lag δ\delta between E⃗\vec{E} and P⃗\vec{P} (due to dielectric relaxation) is the physical mechanism for energy transfer from the wave to the medium.

Misapplying the dot product or ignoring the phase shift leads to calculating the reactive power (using cos⁡δ\cos\delta) instead of the active dissipated power (using sin⁡δ\sin\delta).

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Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptDielectric Polarization Logic
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree