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Question #42762
The Question
A solid conducting sphere of mass and initial radius (measured in a zero-gravity, uncharged state at temperature ) is placed in deep space. It is given a total charge and its temperature is uniformly increased by . The material of the sphere has a uniform bulk modulus and a coefficient of linear thermal expansion . Assuming all deformations are small (), which of the following expressions gives the new interior electrostatic potential of the sphere? \n\n(Given: , is the universal gravitational constant, and is the vacuum permittivity. Assume the sphere remains perfectly spherical.)
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Conductor Interior Potential|Potential vs Field Relationship|Thermal Stress Calculation
Why This Question Is Tricky
Common Mistakes
This question tests the hidden coupling between continuum mechanics and electrostatics.
Students typically fall into the trap of treating conductors as rigid, immutable geometries, calculating the interior potential solely based on the initial radius or only accounting for thermal expansion (Option B).
They fail to account for the mechanical deformation caused by the superposition of Maxwell stress (electrostatic pressure) and self-weight stress (gravitational pressure).
By ignoring the Virial theorem and Hooke's law, they miss that the sphere's capacitance changes due to volumetric strain, which fundamentally shifts the interior potential field.
Option C traps students who invert the signs of the pressures, and Option D traps those who confuse volumetric strain with linear strain.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electrostatic Potential and Capacitance - Class 12 |
| Concept | Conductor Interior Potential |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |