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Question #42762

Difficulty: 8/10 | 🟢 Free

The Question

A solid conducting sphere of mass MM and initial radius R0R_0 (measured in a zero-gravity, uncharged state at temperature T0T_0) is placed in deep space. It is given a total charge QQ and its temperature is uniformly increased by ΔT\Delta T. The material of the sphere has a uniform bulk modulus KK and a coefficient of linear thermal expansion α\alpha. Assuming all deformations are small (ΔR≪R0\Delta R \ll R_0), which of the following expressions gives the new interior electrostatic potential VV of the sphere? \n\n(Given: V0=Q4πϵ0R0V_0 = \frac{Q}{4\pi\epsilon_0 R_0}, GG is the universal gravitational constant, and ϵ0\epsilon_0 is the vacuum permittivity. Assume the sphere remains perfectly spherical.)

Options

  • A.

    V0[1−αΔT−Q296π2ϵ0R04K+GM220πR04K]V_0 \left[ 1 - \alpha \Delta T - \frac{Q^2}{96\pi^2\epsilon_0 R_0^4 K} + \frac{GM^2}{20\pi R_0^4 K} \right]

  • B.

    V0[1−αΔT]V_0 \left[ 1 - \alpha \Delta T \right]

  • C.

    V0[1−αΔT+Q296π2ϵ0R04K−GM220πR04K]V_0 \left[ 1 - \alpha \Delta T + \frac{Q^2}{96\pi^2\epsilon_0 R_0^4 K} - \frac{GM^2}{20\pi R_0^4 K} \right]

  • D.

    V0[1−3αΔT−Q232π2ϵ0R04K+3GM220πR04K]V_0 \left[ 1 - 3\alpha \Delta T - \frac{Q^2}{32\pi^2\epsilon_0 R_0^4 K} + \frac{3GM^2}{20\pi R_0^4 K} \right]

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Conductor Interior Potential|Potential vs Field Relationship|Thermal Stress Calculation

Why This Question Is Tricky

Common Mistakes

This question tests the hidden coupling between continuum mechanics and electrostatics.

Students typically fall into the trap of treating conductors as rigid, immutable geometries, calculating the interior potential solely based on the initial radius or only accounting for thermal expansion (Option B).

They fail to account for the mechanical deformation caused by the superposition of Maxwell stress (electrostatic pressure) and self-weight stress (gravitational pressure).

By ignoring the Virial theorem and Hooke's law, they miss that the sphere's capacitance changes due to volumetric strain, which fundamentally shifts the interior potential field.

Option C traps students who invert the signs of the pressures, and Option D traps those who confuse volumetric strain with linear strain.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptConductor Interior Potential
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree