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Question #42761

Difficulty: 8/10 | 🟢 Free

The Question

A solid, uncharged conducting sphere of radius RR is placed inside a rocket that is accelerating in deep space with a constant acceleration a⃗=ai^\vec{a} = a\hat{i}. Let the center of the sphere be at the origin O(0,0,0)O(0,0,0). Let mem_e and −e-e be the mass and charge of an electron, respectively. Assume that the positive ions of the conductor's lattice are fixed relative to the sphere. Once electrostatic equilibrium is reached in the frame of the rocket, what is the potential difference VA−VOV_A - V_O between the point A(R,0,0)A(R, 0, 0) on the surface of the sphere and the center OO, and what is the induced surface charge density σA\sigma_A at point AA?

Options

  • A.

    VA−VO=meaRe,σA=3ϵ0meaeV_A - V_O = \frac{m_e a R}{e}, \quad \sigma_A = \frac{3 \epsilon_0 m_e a}{e}

  • B.

    VA−VO=meaRe,σA=ϵ0meaeV_A - V_O = \frac{m_e a R}{e}, \quad \sigma_A = \frac{\epsilon_0 m_e a}{e}

  • C.

    VA−VO=0,σA=0V_A - V_O = 0, \quad \sigma_A = 0

  • D.

    VA−VO=−meaRe,σA=−3ϵ0meaeV_A - V_O = -\frac{m_e a R}{e}, \quad \sigma_A = -\frac{3 \epsilon_0 m_e a}{e}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Conductor Interior Potential|Frame of Reference Inertial vs Non-Inertial|Pseudo Force Directionality

Why This Question Is Tricky

Common Mistakes

This question tests the limits of the 'equipotential volume' mnemonic for conductors.

Students are heavily conditioned to assume that the electric field inside a conductor in electrostatic equilibrium is always zero (E=0E=0), which would lead them to incorrectly choose Option C.

However, this rule only applies in an inertial frame without non-electrical body forces.

In an accelerating frame, the pseudo-force acts as an effective uniform gravitational field on the electron gas.

To maintain equilibrium, the electrons must redistribute to create a non-zero internal electric field that exactly cancels the pseudo-force.

A secondary trap (Option B) tests whether students correctly apply the boundary conditions for a polarized sphere (where Ein=σ0/3ϵ0E_{in} = \sigma_0 / 3\epsilon_0) rather than incorrectly applying the infinite slab formula (Ein=σ/ϵ0E_{in} = \sigma / \epsilon_0).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptConductor Interior Potential
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree