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Question #42747
The Question
A modified metre bridge is constructed with a uniform wire AB of length and total resistance . Two resistors and are connected in the left gap (between A and D) and right gap (between D and B) respectively. An ideal battery of emf is connected across the ends A and B (with the positive terminal at A). A non-ideal galvanometer is connected between the junction D and a jockey J that slides on the wire. The galvanometer has a resistance and a mechanical zero error, such that it shows zero deflection only when a constant current flows through it from D to J. Due to the mechanical design of the track, the jockey exerts a variable pressure on the wire, creating a position-dependent contact resistance in series with the galvanometer. For a jockey position (measured from A in cm), this contact resistance is given by . Find the apparent null point position where the galvanometer shows zero deflection.
Options
- A.
90.0 \text{ cm}
- B.
87.6 \text{ cm}
- C.
91.3 \text{ cm}
- D.
75.7 \text{ cm}
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Kirchhoff’s Loop Rule|Metre Bridge End Correction|Binomial Approximation
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to apply Kirchhoff's Loop Rule to a perturbatively unbalanced bridge.
The primary trap lies in the assumption that the bridge's equivalent resistance and the contact resistance can be treated as constants evaluated at the ideal balance point ( cm).
Students who ignore the first-order (linear) variations in and with respect to the displacement will incorrectly calculate the required potential difference to drive the zero-error current , leading to answers like 87.6 cm or 91.3 cm.
By making the contact resistance a function of mechanical displacement, the problem forces a rigorous algebraic formulation of the entire circuit's resistance profile rather than relying on static, ideal-case formulas.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Current Electricity - Class 12 |
| Concept | Kirchhoff’s Loop Rule |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |