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Question #42736

Difficulty: 8/10 | 🟢 Free

The Question

A cell of electromotive force EE and temperature-dependent internal resistance r(T)r(T) is connected across a variable external resistor RR. The internal resistance varies with the cell's temperature TT according to the relation r(T)=r01+α(T−T0)r(T) = \frac{r_0}{1 + \alpha(T - T_0)}, where r0r_0 is the internal resistance at the constant ambient temperature T0T_0, and α\alpha is a positive constant. The cell loses heat to the surroundings at a rate Ploss=k(T−T0)P_{loss} = k(T - T_0), where kk is the heat transfer coefficient. The external resistance RR is continuously adjusted so that the electrical power delivered to it is always maximum. If the cell reaches a steady-state temperature TssT_{ss}, what is the steady-state temperature difference ΔT=Tss−T0\Delta T = T_{ss} - T_0? (Assume 4kr0>E2α4kr_0 > E^2 \alpha)

Options

  • A.

    E24kr0−E2α\frac{E^2}{4kr_0 - E^2 \alpha}

  • B.

    E2kr0−E2α\frac{E^2}{kr_0 - E^2 \alpha}

  • C.

    E24kr0+E2α\frac{E^2}{4kr_0 + E^2 \alpha}

  • D.

    E22kr0−E2α\frac{E^2}{2kr_0 - E^2 \alpha}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Internal Resistance Variation|Temperature and Kinetic Energy|Thermodynamics

Why This Question Is Tricky

Common Mistakes

This question tests the coupling of circuit theory with steady-state thermodynamics, specifically targeting the misconception that internal resistance is a static property.

Students often mechanically apply the Maximum Power Transfer Theorem (R=rR=r) but fail to recognize that the power dissipated internally (I2rI^2r) acts as a heat source that dynamically alters rr itself.

A common trap is calculating the total power E2/rE^2/r instead of the internal dissipation E2/4rE^2/4r, or treating the steady-state condition without accounting for the feedback loop where an increase in temperature lowers resistance, thereby increasing the current and altering the heat generation rate.

This requires setting up a self-consistent energy balance equation rather than a simple sequential calculation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterCurrent Electricity - Class 12
ConceptInternal Resistance Variation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree