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Question #42699

Difficulty: 8/10 | 🟢 Free

The Question

An infinite straight wire carrying a uniform linear charge density λ\lambda is placed along the zz-axis. A sequence of small conducting spheres, numbered n=0,1,2,…n = 0, 1, 2, \dots, each of radius RR, are placed along the xx-axis at positions xn=a⋅2nx_n = a \cdot 2^n (where R≪aR \ll a). Adjacent spheres nn and n+1n+1 are connected by a thin wire with a lumped capacitor of capacitance CC. The self-capacitance of each sphere is C0=4πϵ0RC_0 = 4\pi\epsilon_0 R. Given that C0=43CC_0 = \frac{4}{3}C, and the system is assembled such that the net charge on each isolated section (i.e., sphere nn and the two capacitor plates directly connected to it form an isolated neutral island) is zero, find the steady-state charge Q0Q_0 on the sphere at n=0n=0.

Options

  • A.

    −Rλln⁡2-R \lambda \ln 2

  • B.

    +Rλln⁡2+R \lambda \ln 2

  • C.

    −43Rλln⁡2-\frac{4}{3} R \lambda \ln 2

  • D.

    +34Rλln⁡2+\frac{3}{4} R \lambda \ln 2

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Infinite Series Capacitance|Infinite Wire vs. Finite Wire|Vector Integration

Why This Question Is Tricky

Common Mistakes

This problem tests the superposition of a non-uniform external electric field on an infinite capacitor network.

A common trap is assuming the standard ladder network equations apply directly to the total node potentials, ignoring that the external field biases the self-charge of each node (Qn=C0(Un−Vext)Q_n = C_0(U_n - V_{ext})).

Students might also attempt to sum the induced charges directly, leading to a divergent series.

The key physical insight is recognizing that the logarithmic potential of the infinite wire, when sampled at geometric distances, creates a linear potential bias in the node index nn.

By defining the potential deviation δn=Un−Vext(xn)\delta_n = U_n - V_{ext}(x_n), the non-homogeneous recurrence relation beautifully collapses into a homogeneous one, allowing a clean analytical solution.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptInfinite Series Capacitance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree