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Question #42689

Difficulty: 8/10 | 🟢 Free

The Question

Two large parallel conducting plates of area AA are placed at x=0x = 0 and x=dx = d in vacuum. Both plates are grounded (V=0V = 0). The space between the plates is filled with a frozen-in, non-uniform volume charge density ρ(x)=ρ0xd\rho(x) = \rho_0 \frac{x}{d}, where ρ0\rho_0 is a positive constant. Neglecting edge effects, what is the total electrostatic energy stored in the region between the plates?

Options

  • A.

    ρ02Ad390ϵ0\frac{\rho_0^2 A d^3}{90 \epsilon_0}

  • B.

    ρ02Ad340ϵ0\frac{\rho_0^2 A d^3}{40 \epsilon_0}

  • C.

    ρ02Ad396ϵ0\frac{\rho_0^2 A d^3}{96 \epsilon_0}

  • D.

    ρ02Ad38ϵ0\frac{\rho_0^2 A d^3}{8 \epsilon_0}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Energy Density Locality|Conservative Field Path Independence|Continuous Charge Distribution

Why This Question Is Tricky

Common Mistakes

This question tests the application of Poisson's equation and the locality of energy density in a non-uniform charge distribution.

A common 'Lethal Collision' (trap) is assuming the electric field is simply the integral of the charge density starting from zero (i.e., E(0)=0E(0)=0), which ignores the uniform background field generated by the induced surface charges on the grounded plates.

Students falling for this will incorrectly select the option with denominator 40.

Another trap is treating the system as a standard capacitor with the total integrated charge, or using an average uniform charge density, which fails because electrostatic energy depends non-linearly on the local electric field (u∝E2u \propto E^2).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectrostatic Potential and Capacitance - Class 12
ConceptEnergy Density Locality
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree