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Question #42668
The Question
A uniform electric field exists in a vacuum region (). The electric field lines make an angle with the normal to the - plane (the -axis). The region is filled with a linear, isotropic dielectric material of dielectric constant . There is no free charge on the boundary interface at . Let (in meters) and (in meters) be the perpendicular distances between two adjacent equipotential surfaces separated by the same potential difference (in volts) in the vacuum and the dielectric, respectively. Due to the surface polarization charge density at the interface, the equipotential surfaces exhibit a geometric 'kink'. Calculate the ratio .
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Equipotential Surface Geometry|Superposition Principle|Dielectric Constant (K) Shift|Approximations
Why This Question Is Tricky
Common Mistakes
Students often incorrectly assume that a dielectric simply scales the entire electric field by a factor of (), ignoring the vector nature of the boundary conditions.
This leads to the trap answer of .
In reality, the surface polarization charge density () at the interface only alters the normal component of the electric field, while the tangential component remains continuous.
This differential scaling causes the electric field lines to refract, creating a 'kink' in the equipotential surfaces at the boundary.
The correct geometric relationship requires applying piecewise boundary conditions for and to find the new field magnitude and direction.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electrostatic Potential and Capacitance - Class 12 |
| Concept | Equipotential Surface Geometry |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |