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Question #42636

Difficulty: 8/10 | 🟢 Free

The Question

A damped harmonic oscillator of mass m=1 kgm = 1 \text{ kg} is subjected to a restoring force Fk=−100x NF_k = -100x \text{ N} and a damping force Fd=−2v NF_d = -2v \text{ N}, where xx is the displacement in meters and vv is the velocity in m/s. The oscillator is driven by an external force F(t)=F0(cos⁡(10t)+cos⁡(8t)) NF(t) = F_0 (\cos(10t) + \cos(8t)) \text{ N}, where tt is in seconds. In the steady state, the displacement of the particle is given by the superposition x(t)=A1cos⁡(10t−ϕ1)+A2cos⁡(8t−ϕ2)x(t) = A_1 \cos(10t - \phi_1) + A_2 \cos(8t - \phi_2). What is the value of tan⁡(∣ϕ1−ϕ2∣)\tan(|\phi_1 - \phi_2|)?

Options

  • A.

    94\frac{9}{4}

  • B.

    00

  • C.

    49\frac{4}{9}

  • D.

    11

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Superposition of SHMs|Driven Oscillations and Resonance|Approximation (Binomial)

Why This Question Is Tricky

Common Mistakes

This question targets the misconception that the phase of a driven harmonic oscillator in steady state is identical to the driving force or constant across different frequencies.

Students often assume ϕ1=ϕ2=0\phi_1 = \phi_2 = 0 (leading to an incorrect phase difference of 0) or incorrectly apply the resonance condition to all frequencies.

By forcing the calculation of the frequency-dependent phase lag ϕ=tan⁡−1[bω/(k−mω2)]\phi = \tan^{-1}[b\omega / (k - m\omega^2)], it tests the understanding of dynamics-based superposition where the interference envelope is modulated by the distinct phase lags of each frequency component.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterOscillations - Class 11 Part 2
ConceptSuperposition of SHMs
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree