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Question #42630

Difficulty: 8/10 | 🟢 Free

The Question

A block of mass mm is placed on a smooth horizontal floor of a carriage and attached to a vertical wall of the carriage via a spring of force constant kk and a dashpot of damping coefficient bb. The carriage moves along the horizontal x-axis with an acceleration a(t)=αta(t) = \alpha t for t≥0t \ge 0, where α\alpha is a positive constant. Let x(t)x(t) be the displacement of the block relative to the carriage from the unstretched position of the spring. As t→∞t \to \infty, the phase space trajectory (x(t),v(t))(x(t), v(t)) of the block relative to the carriage converges to a shifting attractor. Identify the coordinates of this attractor (xss(t),vss(t))(x_{ss}(t), v_{ss}(t)).

Options

  • A.

    (−mαkt+bmαk2,−mαk)\left( -\frac{m\alpha}{k}t + \frac{bm\alpha}{k^2}, -\frac{m\alpha}{k} \right)

  • B.

    (−mαkt,−mαk)\left( -\frac{m\alpha}{k}t, -\frac{m\alpha}{k} \right)

  • C.

    (−mαkt−bmαk2,−mαk)\left( -\frac{m\alpha}{k}t - \frac{bm\alpha}{k^2}, -\frac{m\alpha}{k} \right)

  • D.

    (bmαk2,0)\left( \frac{bm\alpha}{k^2}, 0 \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Damped Oscillation Equation|Phase Space Trajectory|Variable Force Integration

Why This Question Is Tricky

Common Mistakes

This question tests the dynamics of a damped oscillator in a non-inertial reference frame with a time-varying acceleration.

The primary trap lies in the assumption that the steady-state equilibrium position is simply determined by balancing the instantaneous pseudo-force with the spring force (kx=−ma(t)kx = -ma(t)).

Students falling for this trap ignore the velocity-dependent damping force's contribution to the steady-state spatial shift.

Because the attractor itself is moving at a constant velocity in phase space, the damper exerts a constant drag force that must be counteracted by an additional constant stretch in the spring, leading to the bmαk2\frac{bm\alpha}{k^2} offset.

This forces a rigorous application of non-homogeneous ODE particular solutions rather than static equilibrium intuition.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterOscillations - Class 11 Part 2
ConceptDamped Oscillation Equation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree