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Question #42612

Difficulty: 8/10 | 🟢 Free

The Question

A fixed point mass MM is located at the origin OO. A smooth rigid circular wire of radius RR is fixed in a plane containing OO, such that its center CC is at a distance 2R2R from OO. A small bead of mass mm is released from rest at the point on the wire farthest from OO. When it reaches the point on the wire closest to OO, it undergoes a perfectly inelastic collision with another stationary bead of mass mm. Find the magnitude of the normal force exerted by the wire on the combined mass immediately after the collision. (Assume GG is the universal gravitational constant)

Options

  • A.

    8GMm3R2\frac{8GMm}{3R^2}

  • B.

    4GMmR2\frac{4GMm}{R^2}

  • C.

    2GMm3R2\frac{2GMm}{3R^2}

  • D.

    5GMm3R2\frac{5GMm}{3R^2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Energy Partitioning|Vertical Circular Motion|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to analyze circular motion in a non-uniform, central gravitational field, bypassing the standard mghmgh approximation.

The primary trap lies in incorrectly assuming a uniform gravitational field g=GM/R2g = GM/R^2 over the path, which leads to an erroneous velocity before collision.

Additionally, students often forget that the centripetal equation requires the vector sum of the normal force and the local gravitational force; neglecting the gravitational pull of the central mass MM on the combined mass 2m2m during the radial force balance yields a severely underestimated normal force.

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Question Information

SubjectPhysics
ChapterOscillations - Class 11 Part 2
ConceptEnergy Partitioning
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree