Start Learning Free

Before You Begin

Question #42562

Difficulty: 8/10 | 🟢 Free

The Question

Consider a classical system of non-interacting particles of mass mm (in kg\text{kg}) constrained to move in a one-dimensional conservative force field. The potential energy of a particle is given by U(x)=αx4U(x) = \alpha x^4, where α\alpha is a positive constant with units of J⋅m−4\text{J} \cdot \text{m}^{-4} and xx is the position in meters. The system is in thermal equilibrium at an absolute temperature TT (in K\text{K}). If kBk_B is the Boltzmann constant, what is the average total mechanical energy per particle?

Options

  • A.

    k_B T

  • B.

    34kBT\frac{3}{4} k_B T

  • C.

    12kBT\frac{1}{2} k_B T

  • D.

    54kBT\frac{5}{4} k_B T

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Equipartition Theorem|Conservative Force Field|Calculus (Integration)

Why This Question Is Tricky

Common Mistakes

This question tests the fundamental limits of the Equipartition Theorem.

Students often blindly memorize that each 'degree of freedom' contributes 12kBT\frac{1}{2}k_B T to the total energy, incorrectly assuming this applies to any potential well.

This trap exposes the misconception by using an anharmonic potential U(x)=αx4U(x) = \alpha x^4.

The equipartition result of 12kBT\frac{1}{2}k_B T strictly requires the energy term to be quadratic in the coordinate or momentum.

By forcing the student to evaluate the partition function integral for a quartic potential, they must realize that ⟨U⟩=14kBT\langle U \rangle = \frac{1}{4}k_B T, yielding a total average energy of 34kBT\frac{3}{4}k_B T instead of the harmonic oscillator's kBTk_B T.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterThermodynamics - Class 11 Part 2
ConceptEquipartition Theorem
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree