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Question #42537

Difficulty: 8/10 | 🟢 Free

The Question

A vertical, perfectly thermally insulated cylinder of cross-sectional area AA contains a monatomic ideal gas. The cylinder is closed by a frictionless, electrically conducting but thermally insulating piston of mass mm. The piston is constrained to move along a frictionless helical groove of pitch pp (vertical displacement pp per revolution). A uniform vertical magnetic field BB exists throughout the region. The center and the rim of the piston are connected via zero-resistance sliding contacts to a heating coil of resistance RR and negligible heat capacity located entirely inside the gas. Initially, the system is in equilibrium with the piston at height h0h_0 and external atmospheric pressure P0P_0. Let P1=P0+mgAP_1 = P_0 + \frac{mg}{A}. A block of mass MM is suddenly placed on the piston. The piston descends, and the system eventually comes to rest at a new equilibrium height hfh_f. Let P2=P0+(m+M)gAP_2 = P_0 + \frac{(m+M)g}{A}. Which of the following expressions gives hfh_f? (Ignore the induced magnetic field).

Options

  • A.

    h0(3P1+2P25P2)h_0 \left( \frac{3 P_1 + 2 P_2}{5 P_2} \right)

  • B.

    h0(P1P2)3/5h_0 \left( \frac{P_1}{P_2} \right)^{3/5}

  • C.

    h0(3P1+2P25P2)exp⁡(−B2A2p2R(M+m)h0g)h_0 \left( \frac{3 P_1 + 2 P_2}{5 P_2} \right) \exp\left( -\frac{B^2 A^2}{p^2 R (M+m)} \sqrt{\frac{h_0}{g}} \right)

  • D.

    h0(2P1+3P25P2)h_0 \left( \frac{2 P_1 + 3 P_2}{5 P_2} \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Internal Energy Dependency|Lenz’s Law Energy Conservation|Motional EMF in Rotating Rods

Why This Question Is Tricky

Common Mistakes

Students often mistakenly decouple the electrodynamics from the thermodynamic cycle, attempting to set up complex differential equations for the damped motion of the piston involving the variable flux coupling and Lenz's law.

The trap lies in failing to recognize that because the heating coil is located inside the gas, the entire system is adiabatically isolated.

By applying the First Law of Thermodynamics to the system as a whole, the internal dissipative forces (magnetic braking) do not change the total energy balance.

The mechanical work done by the external constant pressure and gravity is entirely converted into the internal energy of the gas, making the final equilibrium state completely independent of the magnetic field, resistance, and groove pitch.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterThermodynamics - Class 11 Part 2
ConceptInternal Energy Dependency
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree