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Question #42529

Difficulty: 8/10 | 🟢 Free

The Question

A cylindrical rod of length LL and cross-sectional area AA is placed between two heat reservoirs maintained at temperatures T1=800 KT_1 = 800 \text{ K} (at x=0x = 0) and T2=200 KT_2 = 200 \text{ K} (at x=Lx = L). The thermal conductivity of the rod varies with position xx as k(x)=k0(1+xL)2k(x) = k_0 \left(1 + \frac{x}{L}\right)^2, where k0k_0 is a positive constant. The lateral surface of the rod is perfectly insulated. In the steady state, a small hole is made at the midpoint of the rod (x=L/2x = L/2) to observe the emitted blackbody radiation. If Wien's displacement constant is bb, what is the wavelength λmax\lambda_{\text{max}} corresponding to the maximum spectral emissive power of the radiation emitted from the midpoint?

Options

  • A.

    b400 K\frac{b}{400 \text{ K}}

  • B.

    b500 K\frac{b}{500 \text{ K}}

  • C.

    3b1400 K\frac{3b}{1400 \text{ K}}

  • D.

    b600 K\frac{b}{600 \text{ K}}

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How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Wien’s Displacement Law|Thermal Conductivity in Series and Parallel|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the understanding of steady-state heat conduction in materials with spatially varying thermal conductivity.

A common trap is assuming a linear temperature gradient (yielding an incorrect midpoint temperature of Tmid=500 KT_{mid} = 500 \text{ K}), which is only valid for a constant kk.

Students must recognize that a constant heat flux HH implies dT/dx∝1/k(x)dT/dx \propto 1/k(x), requiring rigorous integration to find the true local temperature before applying Wien's Displacement Law.

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Question Information

SubjectPhysics
ChapterThermal Properties of Matter - Class 11 Part 2
ConceptWien’s Displacement Law
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree