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Question #42516

Difficulty: 8/10 | 🟢 Free

The Question

An ideal gas flows through a cylindrical pipe of diameter DD with a constant uniform velocity vv and at a constant pressure PP. At an initial temperature T0T_0, the mean free path of the gas molecules is λ0\lambda_0 and the Reynolds number of the flow is Re0Re_0. The gas is then heated to a higher temperature such that the mean free path of the molecules becomes 4λ04\lambda_0. Assuming the flow velocity vv and pressure PP remain unchanged, what is the new Reynolds number of the flow? (Assume the gas molecules are hard spheres and follow the standard kinetic theory of gases).

Options

  • A.

    Re08\frac{Re_0}{8}

  • B.

    Re04\frac{Re_0}{4}

  • C.

    Re02\frac{Re_0}{2}

  • D.

    4Re04 Re_0

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Mean Free Path|Reynolds Number Transition|Variation of Density with Temperature

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to connect macroscopic fluid dynamics (Reynolds number) with microscopic kinetic theory.

A common trap is assuming that the dynamic viscosity of a gas is independent of temperature, which would incorrectly lead to Re∝ρ∝1/TRe \propto \rho \propto 1/T, yielding Re0/4Re_0/4.

Another trap is ignoring the density variation and only considering viscosity, yielding Re0/2Re_0/2.

By forcing the derivation of both ρ∝1/T\rho \propto 1/T and η∝T\eta \propto \sqrt{T} from kinetic theory principles, the problem elegantly exposes superficial dimensional analysis and rote memorization.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterKinetic Theory - Class 11 Part 2
ConceptMean Free Path
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree