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Question #42491
The Question
A parallel plate capacitor with rectangular plates of length and width , separated by a distance , is connected to a constant voltage source . A dielectric slab of mass , length , width , and thickness is attached to a relaxed spring of spring constant . The other end of the spring is fixed. The slab is partially inserted into the capacitor by a distance (where corresponds to the spring being relaxed and the slab just at the edge of the capacitor). The dielectric constant of the slab varies along its length as , where is the distance from the leading edge of the slab. Ignore fringe effects and assume parameters allow a non-zero equilibrium position . Determine the nature of the equilibrium at and the effective force constant .
Options
- A.
\text{Unstable, } -k
- B.
\text{Stable, } k
- C.
\text{Unstable, } -2k
- D.
\text{Stable, } 2k
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Equilibrium Stability|Non-Uniform Dielectric Filling|Conservative Force Field|Calculus
Why This Question Is Tricky
Common Mistakes
This question tests the rigorous application of the Virtual Work principle and stability analysis in electrostatics.
The primary trap lies in the non-uniform dielectric creating a non-linear electrostatic force that overpowers the linear spring force at the equilibrium point.
Students commonly assume that any equilibrium involving a restoring spring is stable, or they incorrectly use without accounting for the work done by the battery, leading to incorrect force gradients.
The negative second derivative explicitly proves instability, defying the intuitive assumption of simple harmonic motion.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Work, Energy, and Power - Class 11 Part 1 |
| Concept | Equilibrium Stability |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |