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Question #42477

Difficulty: 8/10 | 🟢 Free

The Question

A small bead of mass mm is threaded on a fixed, smooth vertical circular wire of radius RR. The bead is projected from the lowest point of the wire with an initial speed v0v_0. As it moves, it experiences a tangential air drag force of magnitude Fd=m2Rv2F_d = \frac{m}{2R}v^2, where vv is its instantaneous speed. What is the minimum initial speed v0v_0 required for the bead to just reach the highest point of the circular wire?

Options

  • A.

    gR(eπ+1)\sqrt{gR(e^\pi + 1)}

  • B.

    gR(eπ−1)\sqrt{gR(e^\pi - 1)}

  • C.

    2gR(eπ+1)\sqrt{2gR(e^\pi + 1)}

  • D.

    gR(eπ/2+1)\sqrt{gR(e^{\pi/2} + 1)}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Work-Energy Theorem Validity|Vertical Circular Motion|Non-Uniform Circular Motion

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Work-Energy Theorem in the presence of a path-dependent, non-conservative drag force.

Students commonly fall into the trap of attempting to use simple mechanical energy conservation (Ei=EfE_i = E_f) or incorrectly integrating the drag force without coupling it to the kinematics.

By introducing a velocity-squared dependent drag, the problem forces the student to express the tangential acceleration as vdvdsv \frac{dv}{ds} and construct a first-order linear differential equation in v2v^2 with respect to the angular position θ\theta.

This rigorously evaluates their ability to transform a path integral of a non-conservative force into a solvable angular differential equation, bridging advanced mechanics with calculus.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWork, Energy, and Power - Class 11 Part 1
ConceptWork-Energy Theorem Validity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree