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Question #42460

Difficulty: 8/10 | 🟢 Free

The Question

A nucleus AA of mass 6m6m is initially at rest in the laboratory frame. It undergoes a radioactive decay into a nucleus BB of mass 4m4m and a particle CC of mass 2m2m, releasing a total kinetic energy of 4Q4Q. Subsequently, while in flight, nucleus BB decays into a nucleus DD of mass 3m3m and a particle EE of mass mm, releasing a total kinetic energy of QQ. Assuming all decays are isotropic in their respective center-of-mass frames and non-relativistic mechanics applies, what is the maximum possible kinetic energy of nucleus DD in the laboratory frame?

Options

  • A.

    94Q\frac{9}{4}Q

  • B.

    52Q\frac{5}{2}Q

  • C.

    1912Q\frac{19}{12}Q

  • D.

    14Q\frac{1}{4}Q

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Impulse-Momentum Theorem|Frame of Reference|Successive Decay Equilibrium

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Impulse-Momentum Theorem and Galilean velocity addition across changing reference frames in successive decays.

The primary trap is the 'Single-Event Conservation' fallacy, where students incorrectly lump the sequential decays into a single simultaneous 3-body decay (A→C+D+EA \rightarrow C + D + E) with total energy 5Q5Q.

This flawed assumption allows momentum to be shared arbitrarily among all three particles, yielding an artificially high maximum kinetic energy (52Q\frac{5}{2}Q) for particle DD by assuming CC and EE recoil together.

By enforcing the intermediate state (nucleus BB), the physical constraints of the sequential momentum impulses are respected, demonstrating that steady-state energy conservation cannot bypass the time-dependent momentum distribution of intermediate frames.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterLaws of Motion - Class 11 Part 1
ConceptImpulse-Momentum Theorem
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree