Before You Begin
Question #42460
The Question
A nucleus of mass is initially at rest in the laboratory frame. It undergoes a radioactive decay into a nucleus of mass and a particle of mass , releasing a total kinetic energy of . Subsequently, while in flight, nucleus decays into a nucleus of mass and a particle of mass , releasing a total kinetic energy of . Assuming all decays are isotropic in their respective center-of-mass frames and non-relativistic mechanics applies, what is the maximum possible kinetic energy of nucleus in the laboratory frame?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Impulse-Momentum Theorem|Frame of Reference|Successive Decay Equilibrium
Why This Question Is Tricky
Common Mistakes
This question tests the application of the Impulse-Momentum Theorem and Galilean velocity addition across changing reference frames in successive decays.
The primary trap is the 'Single-Event Conservation' fallacy, where students incorrectly lump the sequential decays into a single simultaneous 3-body decay () with total energy .
This flawed assumption allows momentum to be shared arbitrarily among all three particles, yielding an artificially high maximum kinetic energy () for particle by assuming and recoil together.
By enforcing the intermediate state (nucleus ), the physical constraints of the sequential momentum impulses are respected, demonstrating that steady-state energy conservation cannot bypass the time-dependent momentum distribution of intermediate frames.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Laws of Motion - Class 11 Part 1 |
| Concept | Impulse-Momentum Theorem |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |