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Question #42395

Difficulty: 8/10 | 🟢 Free

The Question

A uniform rectangular block of mass mm, height hh, and base width bb is released from rest on an inclined plane making an angle θ\theta with the horizontal. A thin layer of fluid on the incline exerts a viscous drag force on the block of magnitude Fv=kvF_v = kv directed up the incline, where vv is the instantaneous velocity of the block and kk is a positive constant. The drag force acts uniformly over the bottom face of the block. Given that tan⁡θ>bh\tan\theta > \frac{b}{h}, the block will eventually topple forward. Find the time tt after release at which the block begins to topple.

Options

  • A.

    mkln⁡(htan⁡θhtan⁡θ−b)\frac{m}{k} \ln\left( \frac{h \tan\theta}{h \tan\theta - b} \right)

  • B.

    mkln⁡(htan⁡θhtan⁡θ+b)\frac{m}{k} \ln\left( \frac{h \tan\theta}{h \tan\theta + b} \right)

  • C.

    mkln⁡(btan⁡θbtan⁡θ−h)\frac{m}{k} \ln\left( \frac{b \tan\theta}{b \tan\theta - h} \right)

  • D.

    mkln⁡(hsin⁡θhsin⁡θ−b)\frac{m}{k} \ln\left( \frac{h \sin\theta}{h \sin\theta - b} \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Toppling vs Sliding|Viscosity and Stokes' Law|Work, Energy, and Power

Why This Question Is Tricky

Common Mistakes

Students often incorrectly assume that the normal force always acts through the center of mass, or they calculate torques about the toppling edge but forget to account for the non-inertial pseudo force (or the rate of change of angular momentum in the lab frame) due to the block's acceleration.

By placing the velocity-dependent drag force at the bottom face, the problem forces students to recognize that the drag induces a tipping torque about the center of mass.

This torque must be balanced by a forward shift in the normal force's line of action.

The trap is failing to couple the rotational equilibrium condition (which gives a critical velocity for toppling) with the translational first-order differential equation (which gives velocity as a function of time).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterSystem of Particles and Rotational Motion - Class 11 Part 1
ConceptToppling vs Sliding
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree